Question

我是JS的新手，正在制作一个小型的数学游戏。在JSHint上它说我在一行上缺少一个分号，我不是，它不会在我的浏览器中运行，我会发布代码，有人可以告诉我我做错了什么。谢谢！

var newMathGame = function() {
    var points = 1;
    var numberOfQuestions = prompt("How many questions would you like?");
    var highestNumber = prompt(
        "What is the highest number you would like to be quizzed on?");
    var whichGame = prompt(
        "Would you you like to play\n 'SUBTRACTION', 'ADDITION', 'MULTIPLICATION' or 'DIVISION'?"
    ).toUpperCase();
    switch (whichGame) {
        case 'ADDITION':
            addition();
            break;
        case 'SUBTRACTION':
            subtraction();
            break;
        case 'DIVISION':
            division();
            break;
        case 'MULTIPLICATION':
            multiplication();
            break;
    }

    function subtraction() {
        for (var count = 0; count < numberOfQuestions; count++) {
            var x = Math.floor((Math.random() * 10) + 1);
            var y = Math.floor((Math.random() * 10) + 1);
            if (x < y) {
                subtraction();
            } else {
                var answer = (x - y);
                var user_answer = prompt(x + "-" + y);
                if (answer == user_answer) {
                    alert("Yes!");
                } else {
                    alert("No! The answer is " + answer);
                }
            }
        }
    }

    function addition() {
        for (var count = 0; count < numberOfQuestions; count++) {
            var x = Math.floor((Math.random() * 10) + 1);
            var y = Math.floor((Math.random() * 10) + 1);
            var answer = (x + y);
            var user answer = (x + "+" + y); //says I am missing semicolon on this line
            if (answer == user_answer) {
                alert("Yes!");
            } else {
                alert("No! The answer is " + answer);
            }
        }
    }
};

Answer 1

变量名user answer无效，因为它有空格。看起来应该是user_answer。

Answer 2

您的问题是该变量之前被称为user_answer，但您的行说明要检查的变量称为user answer。 JavaScript和许多其他编译器使用单字变量。要让编译器停止翻转，请在错误所在的位置添加下划线，使其显示为user_answer。

Answer 3

这一行在语法上是不正确的。变量名称不能包含空格。

var user answer = (x + "+" + y);

调试器可能认为你想要

var user;
answer = (x + "+" + y);

这将非常有意义。

说我缺少分号，我不是

3 个答案: