尽管谷歌搜索了2个小时并尝试了各种JOINS和UNIONS和ALIASES以及诸如此类的东西,我仍然无法在一个表中检索来自WordPress数据库的wp_postmeta表中的两个子查询的结果(我甚至都没有在这里关心wp_posts,我感兴趣的所有数据都在postmeta中。
我有自定义字段(使用ACF插件管理),在数据库中看起来如下所示,其中一个键用于区域,另一个键用于数值。
| ID | meta_key | meta_value |
| 1 | group_name | Japan |
| 1 | facility_index | 0.83 |
| 2 | group_name | USA |
| 2 | facility_index | 4.51 |
我需要一个返回以下内容的查询,以便我可以按区域计算聚合(例如,所有工具的facility_index的总和,按国家/地区,即按group_name):
| ID | group_name | facility_index |
| 1 | Japan | 0.83 |
| 2 | USA | 4.51 |
此查询列出了group_name两次,而不是列出第3列中的facility_index:
SELECT post_id, meta_value, result2.meta_value FROM
(
(
SELECT post_id, meta_value
FROM wp_postmeta
WHERE meta_key = "group_name"
)
UNION
(
SELECT post_id, meta_value
FROM wp_postmeta
WHERE meta_key = "facility_index"
)
) AS result2
GROUP BY post_id
编辑以显示完全符合我想要的最终查询,这要归功于下面接受的答案:
SELECT
meta1.meta_value AS group_name,
meta2.meta_value AS facility_index,
SUM(meta2.meta_value) AS 'fac_index_geo'
FROM wp_posts post
LEFT JOIN wp_postmeta meta1 ON meta1.post_id = post.ID AND meta1.meta_key = 'group_name'
LEFT JOIN wp_postmeta meta2 ON meta2.post_id = post.ID AND meta2.meta_key = 'facility_index'
WHERE
post.post_type = 'facility'
GROUP BY group_name
答案 0 :(得分:2)
据我所知,您正在寻找自定义SQL查询 - 即您不想使用WP_Query
对象。
为此我会使用一些JOINS而不是子查询。
另外,我建议您查询post_type
,否则您可能会从自动保存/修订或类似的错误结果中获取数据。
/*
INNER JOIN
This query will only return posts that contain all meta values
i.e. all 'post' items with group_name AND facility_index
*/
$sql = "
SELECT
post.ID,
meta1.meta_value AS group_name,
meta2.meta_value AS facility_index
FROM {$wpdb->posts} post
INNER JOIN {$wpdb->postmeta} meta1 ON meta1.post_id = post.ID AND meta1.meta_key = 'group_name'
INNER JOIN {$wpdb->postmeta} meta2 ON meta2.post_id = post.ID AND meta2.meta_key = 'facility_index'
WHERE
post.post_type = 'post'
";
$data = $wpdb->get_results( $sql );
只需确保更新post_type条件以匹配您所需的帖子类型。
或者,如果您还想获得缺少元值的帖子,可以使用此查询
/*
LEFT JOIN
This query will return all posts even if they have missing meta values
i.e. if group_name or facility_index is empty, then NULL is returned in the column
*/
$sql = "
SELECT
post.ID,
meta1.meta_value AS group_name,
meta2.meta_value AS facility_index
FROM {$wpdb->posts} post
LEFT JOIN {$wpdb->postmeta} meta1 ON meta1.post_id = post.ID AND meta1.meta_key = 'group_name'
LEFT JOIN {$wpdb->postmeta} meta2 ON meta2.post_id = post.ID AND meta2.meta_key = 'facility_index'
WHERE
post.post_type = 'post'
";