Question

我正在尝试使用xslt打印平均值，并且很难找到方法。我在单独的节点中有答案，在单独的节点中有问题。需要将问题ID与答案进行匹配并计算平均值

<?xml version="1.0" encoding="ISO-8859-1"?>
 <?xml-stylesheet type="text/xsl" href="test.xsl"?>
   <details>
     <detail>
      <answersall>
        <answers>
          <question id="1"/>
          <answer>4</answer>
          <note>test</note>
      </answers>
      <answers>
        <question id="2"/>
        <answer>2</answer>
      </answers>
      <answers>
        <question id="3"/>
        <answer>2</answer>
      </answers>
      <answers>
        <question id="4"/>
        <answer>3</answer>
      </answers>
    </answerall>
  </detail>
  <questions>
   <question id="1" text="Hello how are you" section="a"/>
   <question id="2" text="how was your day" section="a"/>
   <question id="3" text="it was good" section="b"/>
   <question id="4" text="take care" section="b"/>
  </questions>
</details>

我正在尝试打印这样的东西 Question Answer
Section A 3 (average)
1. Hello how are you 4
2.How was your day 2
Section B 2.5
3. It was good 2
4. Take Care 3

我有部分打印问题和答案，但不是平均值。我知道我不能在for循环中使用变量。

下面是我的xslt。

<?xml version="1.0" ?>
 <xsl:stylesheet version="1.0"    xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
  <xsl:template match="/">
   <html>
     <body>
      <h2><center>Details</center></h2>
       <table>
         <tr>
           <td>Section A</td>
           <td>????</td>
         </tr>
         <xsl:for-each select="details/questions/question[@section='a']">
           <xsl:variable name="id" select="@id"/>
             <tr>
                <td><xsl:value-of select="@text"/></td>
                <td><xsl:value-of select="//answers[question/@id=$id]/answer"/></td>
             </tr>
         </xsl:for-each>
     </table>
  </body>
</html>

Answer 1

以下是您可以用作起点的内容：

XSLT 1.0

<xsl:stylesheet version="1.0" 
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes"/>
<xsl:strip-space elements="*"/>

<xsl:key name="question-by-section" match="question" use="@section" />
<xsl:key name="answer-by-question" match="answers" use="question/@id" />

<xsl:template match="/">
    <table border="1">
        <tr>
            <th>Question</th>
            <th>Answer</th>
        </tr>
        <xsl:call-template name="generate-section">     
            <xsl:with-param name="section">a</xsl:with-param>
        </xsl:call-template>
        <xsl:call-template name="generate-section">     
            <xsl:with-param name="section">b</xsl:with-param>
        </xsl:call-template>
     </table>
</xsl:template>

<xsl:template name="generate-section">
    <xsl:param name="section"/>
    <xsl:variable name="questions" select="key('question-by-section', $section)" />
    <xsl:variable name="answers" select="key('answer-by-question', $questions/@id)" />
    <tr>
        <th>
            <xsl:value-of select="concat('Section ', $section)" />
        </th>
        <th>
            <xsl:value-of select="sum($answers/answer) div count($answers)" />          
        </th>
    </tr>
    <xsl:for-each select="$questions">
        <tr>
            <td><xsl:value-of select="@text"/></td>
            <td><xsl:value-of select="key('answer-by-question', @id)/answer"/></td>
        </tr>
    </xsl:for-each>
</xsl:template>

</xsl:stylesheet>

应用于您的输入（在纠正answersall vs answerall不匹配后！），结果将如下所示：

enter image description here

我强烈建议您采用Muenchian grouping来选择不同的部分，而不是对此处显示的命名模板进行硬编码的重复调用。

用xslt计算平均值

1 个答案: