Question

我在这里发现了一些类似的帖子，但不适用于我想做的事情......

类似的帖子：Trying to write a query that counts multiple things with different where cases

类似的帖子：Query that Counts records with a WHERE clause

我想要做的是我有一些...... 200组，在这些组中是具有特定申请日期的人。我想要计算那些申请日期在特定范围内的群体中有多少人。

所以这是我一直使用的第一种方法，但它一次只适用于1组

SELECT count(*) as count
FROM membersapplication ma
INNER JOIN members mb on mb.mbr_id = ma.mbr_id
WHERE (GPL_ID = 20179) and (ma.mpl_effectivedate >= '2/01/2015' and ma.mpl_effectivedate <= '4/30/2015') and (ma.mpl_cancellationdate is null)

此代码记录了GPL_ID 20179（组位置ID）下的任何人的数量，我有200个GPL_ID，我希望它能运行，没有重复的GPL_ID。

SELECT Gr.GPL_ID, Gr.GPL_Effectivedate, G.GRP_Enrolltype, G.GRP_Name, G.GRP_ID, G.GRP_Executive
FROM groupsreview gr
INNER JOIN groups g on gr.grp_ID = g.grp_ID
WHERE (GRP_ENROLLTYPE = 1) and (gp.gpl_effectivedate >= '4/30/2014' and gp.gpl_effectivedate <= '4/30/2015')
order by grp_name asc

此代码为我提供了我想要的每个GPL_ID列表（基于GRP_Enrolltype = 1），该列表属于我想要的日期范围

我基本上想要合并这两个代码，以便第二组代码添加另一个具有基于第一个代码的计数的列

Answer 1

不确定这是否有效，但我可以尝试一下：

SELECT 
    *
FROM
    (SELECT 
        count(*) as count, GPL_ID
    FROM
        membersapplication ma
    inner join members mb ON mb.mbr_id = ma.mbr_id
    where
        (ma.mpl_effectivedate >= '2/01/2015'
            and ma.mpl_effectivedate <= '4/30/2015')
            and (ma.mpl_cancellationdate is null)
    GROUP BY GPL_ID) T1
        INNER JOIN
    (SELECT 
        Gr.GPL_ID,
            Gr.GPL_Effectivedate,
            G.GRP_Enrolltype,
            G.GRP_Name,
            G.GRP_ID,
            G.GRP_Executive
    FROM
        groupsreview gr
    inner join groups g ON gr.grp_ID = g.grp_ID
    WHERE
        (GRP_ENROLLTYPE = 1)
            and (gp.gpl_effectivedate >= '4/30/2014'
            and gp.gpl_effectivedate <= '4/30/2015')) T2 
   ON T1.GPL_ID = T2.GPL_ID

Answer 2

似乎您真的只需要在查询中添加GROUP BY：

SELECT ma.GPL_ID, count(*) as count
FROM membersapplication ma
INNER JOIN members mb 
ON mb.mbr_id = ma.mbr_id
where (ma.mpl_effectivedate >= '2/01/2015' and ma.mpl_effectivedate <= '4/30/2015') 
AND (ma.mpl_cancellationdate is null)
GROUP BY ma.GPL_ID

Answer 3

这应该这样做。但我会仔细检查日期，我只使用你提供的日期;他们不匹配，我不确定他们是否应该：

SELECT ma.GPL_ID, count(*) as count
FROM groups g
INNER JOIN groupsreview AS gr ON g.grp_ID = gr.grp_ID 
INNER JOIN membersapplication AS ma ON gr.GPL_ID = ma.GPL_ID
INNER JOIN members AS mb ON mb.mbr_id = ma.mbr_id
WHERE g.GRP_ENROLLTYPE = 1 
   AND gr.gpl_effectivedate BETWEEN 20140430 AND 20150430
   AND ma.mpl_effectivedate BETWEEN 20150201 and 20150430 
   AND ma.mpl_cancellationdate IS NULL
GROUP BY ma.GPL_ID
;

从您的问题的措辞来看，按GPL_ID而不是grp_ID分组感觉有点奇怪。

Answer 4

基本上你应该通过组合连接然后在GPL_ID和has子句上进行分组来解决这个问题。这就是我们想到的。

SELECT Gr.GPL_ID, Gr.GPL_Effectivedate, G.GRP_Enrolltype, G.GRP_Name, G.GRP_ID, G.GRP_Executive
count(*) as grp_count
FROM membersapplication ma
INNER JOIN members mb on mb.mbr_id = ma.mbr_id
INNER JOIN groupsreview gr on mb.GPL_ID = gr.GPL_ID
INNER JOIN groups g on gr.grp_ID = g.grp_ID
WHERE (GRP_ENROLLTYPE = 1) and (gp.gpl_effectivedate >= '4/30/2014' and gp.gpl_effectivedate <= '4/30/2015')
GROUP BY Gr.GPL_ID, Gr.GPL_Effectivedate, G.GRP_Enrolltype, G.GRP_Name, G.GRP_ID, G.GRP_Executive
HAVING (ma.mpl_effectivedate >= '2/01/2015' and ma.mpl_effectivedate <= '4/30/2015') and (ma.mpl_cancellationdate is null)
order by grp_name asc

希望这会有所帮助

将2组合为1的SQL查询，特别是它计算每个组中每组中的人数

4 个答案: