Question

我有一个流程价格的程序，在慢时间内收到badstatusline错误。这会导致需要与流交互的其他文件出现问题。我只是在捕捉异常时遇到了很多麻烦，导致我因某些原因无法捕获的其他异常BadStatusLine导致CannotSendRequest导致ResponseNotReady。当execution.py引发异常BadStatusLine时，我怎样才能简单地重启（在这种情况下）trading.py？

以下是我现在处理它的方式..

while True:
    try:
        response = self.conn.getresponse().read()
        print response
    except Exception:
        pass 
    else:
        break

使用Httplib的流是重要的

感谢您的帮助

这也是错误：

Exception in thread Thread-1:
Traceback (most recent call last):
  File "/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/threading.py", line 810, in __bootstrap_inner
    self.run()
  File "/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/threading.py", line 763, in run
    self.__target(*self.__args, **self.__kwargs)
  File "/Users/mattduhon/trading4.py", line 30, in trade
    execution.execute_order(event)
  File "/Users/mattduhon/execution.py", line 34, in execute_order
    response = self.conn.getresponse().read()
  File "/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/httplib.py", line 1073, in getresponse
    response.begin()
  File "/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/httplib.py", line 415, in begin
    version, status, reason = self._read_status()
  File "/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/httplib.py", line 379, in _read_status
    raise BadStatusLine(line)
BadStatusLine: ''

Answer 1

如果你是连续文件，那么你可以把它放在主管并添加

auto_start = True

或者在您的代码中，您可以执行类似的操作

import os
while True:
            try:
                response = self.conn.getresponse().read()
                    print response
            except:
                os.system("python trading.py")

我添加了广泛的异常，因为您不知道发生了哪个异常

Answer 2

创建另一个脚本来运行主脚本，并try和except创建整个脚本：

try:
    execfile('main.py')

except:
    pass

错误后重启python文件

2 个答案: