select t1.TITLE,PJT_ID, group_concat(t2.count) as COUNT, group_concat(t2.CREATED_BY) USERS,t2.task_id,group_concat(dc_users.PHOTO)as PHOTO from dc_tasks t1 inner join (SELECT dc_remarks.`CREATED_BY`,dc_sprints.PJT_ID , TSK_ID AS task_id, count( dc_remarks.`CREATED_BY` ) AS count FROM dc_remarks inner join dc_tasks on dc_remarks.`TSK_ID` = dc_tasks.ID inner join dc_sprints on dc_sprints.ID=dc_tasks.SPT_ID WHERE DATE( `CREATED_ON` ) = DATE('2015-05-22') AND dc_sprints.PJT_ID = GROUP BY `CREATED_BY` , `TSK_ID` ORDER BY `TSK_ID`) t2 on t1.ID = t2.task_id inner join dc_users on dc_users.FIRST_NAME = t2.CREATED_BY GROUP BY t2.task_id
答案 0 :(得分:1)
您的错误在这里:
dc_sprints.PJT_ID = GROUP BY `CREATED_BY`.
在分组结果之前完成where条件
您的格式化的SQL看起来像这样:
select
t1.TITLE,PJT_ID, group_concat(t2.count) as COUNT,
group_concat(t2.CREATED_BY)
USERS,t2.task_id,group_concat(dc_users.PHOTO)as PHOTO
from
dc_tasks t1
inner join (
SELECT
dc_remarks.`CREATED_BY`,dc_sprints.PJT_ID ,
TSK_ID AS task_id, count( dc_remarks.`CREATED_BY` ) AS count
FROM
dc_remarks
inner join dc_tasks on dc_remarks.`TSK_ID` = dc_tasks.ID
inner join dc_sprints on dc_sprints.ID=dc_tasks.SPT_ID
WHERE
DATE( `CREATED_ON` ) = DATE('2015-05-22') AND
dc_sprints.PJT_ID =
GROUP BY `CREATED_BY` , `TSK_ID` ORDER BY `TSK_ID`
) t2 on t1.ID = t2.task_id
inner join dc_users on dc_users.FIRST_NAME = t2.CREATED_BY
GROUP BY t2.task_id
答案 1 :(得分:-1)
select
t1.TITLE,PJT_ID, group_concat(t2.count) as COUNT,
group_concat(t2.CREATED_BY)
USERS,t2.task_id,group_concat(dc_users.PHOTO)as PHOTO
from
dc_tasks t1
inner join (
SELECT
dc_remarks.`CREATED_BY`,dc_sprints.PJT_ID ,
TSK_ID AS task_id, count( dc_remarks.`CREATED_BY` ) AS count
FROM
dc_remarks
inner join dc_tasks on dc_remarks.`TSK_ID` = dc_tasks.ID
inner join dc_sprints on dc_sprints.ID=dc_tasks.SPT_ID
WHERE
DATE( `CREATED_ON` ) = DATE('2015-05-22') AND
dc_sprints.PJT_ID = dc_tasks.project_id
GROUP BY `CREATED_BY` , `TSK_ID` ORDER BY `TSK_ID`
) t2 on t1.ID = t2.task_id
inner join dc_users on dc_users.FIRST_NAME = t2.CREATED_BY
GROUP BY t2.task_id