Question

我有2 ViewControllers。 1是用于具有计时器的游戏。第二个是结果。在游戏ViewController上按完成按钮后，它会转到结果。如何在结果ViewController上的标签上显示计时器的结果？

这是我的计时器代码：

//these are initialized in games ViewController.h
IBOutlet UILabel *GameTimer;
int timeSec;
int timeMin;
NSTimer *timer;

//game ViewController.m under @implementation
INSString *timeNow;
NSTimer *timer1;

这是我的计时器方法：

- (void)viewDidLoad {
    [super viewDidLoad];
    // Do any additional setup after loading the view.

    [self performSelector:@selector(startTimer1) withObject: nil afterDelay:0.0];

}
- (void)didReceiveMemoryWarning {
    [super didReceiveMemoryWarning];
    // Dispose of any resources that can be recreated.
}
-(void)startTimer1{

    //initializing 'timer1'
    timer1 = [NSTimer scheduledTimerWithTimeInterval:1.0
                                              target:self
                                            selector:@selector(timerTick:)
                                            userInfo:nil
                                             repeats:YES];
    [[NSRunLoop currentRunLoop] addTimer:timer1 forMode:NSDefaultRunLoopMode];
}
//Event called every time the NSTimer ticks.
- (void)timerTick:(NSTimer *)timer1
{
    timeSec++;
    if (timeSec == 60)
    {
        timeSec = 0;
        timeMin++;
    }
    //Format the string 00:00
    timeNow = [NSString stringWithFormat:@"Tiempo: %02d:%02d", timeMin, timeSec];
    //Display on your label
    //[timeLabel setStringValue:timeNow];
    GameTimer.text= timeNow;
}
//Call this to stop the timer event(could use as a 'Pause' or 'Reset')
- (void) StopTimer
{
    [timer invalidate];
    timeSec = 0;
    timeMin = 0;
    //Since we reset here, and timerTick won't update your label again, we need to refresh it again.
    //Format the string in 00:00
    timeNow = [NSString stringWithFormat:@"%02d:%02d", timeMin, timeSec];
    //Display on your label
    // [timeLabel setStringValue:timeNow];
    GameTimer.text= timeNow;
}
//executed after the finish button is pressed
- (IBAction)finishPressed:(id)sender{
}

编辑：

- (void)prepareForSegue:(UIStoryboardSegue *)segue sender:(id)sender
{

    LetterResults6x6 *nextViewController = [[LetterResults6x6 alloc] initWithNibName:@"ViewController" bundle:nil]; //Let us assume that ViewController is the controller in which you wish to show the result.
    nextViewController.finalTime = timeNow; //here finalTime is a NSString property in ViewController Class
    [self.navigationController pushViewController:nextViewController animated:YES];
}
- (IBAction)finishPressed:(id)sender
{

    [self performSegueWithIdentifier: @"finished" sender: self];

}

编辑2解决方案：我想到了。我通过向计时器方法添加几行代码来记录结果，然后在另一个ViewController

中传递它们，从而更容易地实现了这一点。

- (void)timerTick:(NSTimer *)timer1
{
    timeSec++;
    if (timeSec == 60)
    {
        timeSec = 0;
        timeMin++;
    }
    //Format the string 00:00
    timeNow = [NSString stringWithFormat:@"Tiempo: %02d:%02d", timeMin, timeSec];
    //Display on your label
    //[timeLabel setStringValue:timeNow];
    GameTimer.text= timeNow;
    //code i added
    NSUserDefaults *prefs1 = [NSUserDefaults standardUserDefaults];
    [prefs1 setObject:[NSString stringWithFormat:@"%@",timeNow] forKey:@"keyToLookupString"];
}

然后将其添加到第二个ViewController .m

NSUserDefaults *prefs1 = [NSUserDefaults standardUserDefaults];
NSString *sc = [prefs1 stringForKey:@"keyToLookupString"];

timerResults.text = [NSString stringWithFormat:@"tiempo %@", sc];

感谢所有帮助人员：）

Answer 1

你应该在推送它时将字符串值传递给下一个控制器，

如果您使用.xib

ViewController *nextViewController = [[ViewController alloc] initWithNibName:@"ViewController" bundle:nil]; //Let us assume that ViewController is the controller in which you wish to show the result.
nextViewController.finalTime = timeNow; //here finalTime is a NSString property in ViewController Class
[self.navigationController pushViewController:nextViewController animated:YES];

对于Storyboard，请使用此代码

- (void)prepareForSegue:(UIStoryboardSegue *)segue sender:(id)sender
{
    if ([segue.destinationViewController isKindOfClass:[ViewController class]]) {//Let us assume that ViewController is the controller in which you wish to show the result(i.e., Second controller).
        nextViewController.finalTime = timeNow; //here finalTime is a NSString property in ViewController Class
    }
}

修改

在第一个视图控制器.m文件
中
//executed after the finish button is pressed - (IBAction)finishPressed:(id)sender{ } - (void)prepareForSegue:(UIStoryboardSegue *)segue sender:(id)sender { if ([segue.destinationViewController isKindOfClass:[LetterResults6x6 class]]) { nextViewController.finalTime = timeNow; //here finalTime is a NSString property in ViewController Class } }

在LetterResults6x6.h

@property (nonatomic, retain) NSString *finalTime;

在LetterResults6x6.m

- (void)viewDidLoad { [super viewDidLoad]; self.labelOutlet.text = self.finalTime; }

Answer 2

在推送timeSec时，只需传递timeMin和resultsViewController的值。

在ResultsViewController.h中添加此属性

@property (nonatomic) int  timeSec;
@property (nonatomic) int  timeMin;

现在在GameViewController中，在此方法中添加以下内容： -

//executed after the finish button is pressed
- (IBAction)finishPressed:(id)sender{
  ResultsViewController *resultViewController = [self.storyboard instantiateViewControllerWithIdentifier:@"ResultsViewController"];
   resultViewController.timeMin=timeMin;  //pass the value
   resultViewController.timeMin=timeSec;  //pass the value

  // now push to your ResultViewController

}

如何在下一个`ViewController'上显示Timer结果

2 个答案: