Question

a = [2, 2, 4, 2, 5, 7]

如果要查找此列表中的最小值（2），列表2中a的相应索引分别为0,1和3。

如何告诉python使用最高索引处的最小值（索引3处的数字2）？

Answer 1

您可以使用a[::-1]简单地反转列表，然后应用相同的技术来查找索引。 a[::-1].index(min(a))将为我们提供最终值的索引，为了将索引记录到第0个位置（列表的开头），我们可以从a[::-1].index(min(a))中减去len(a) - 1。

a = [2, 2, 4, 2, 5, 7]

print len(a) - a[::-1].index(min(a)) - 1

>>> 3

Answer 2

这可以写成函数max()，然后获取生成的迭代器的def indexes(xs, value): for i, x in enumerate(xs): if x == value: yield i a = [2, 2, 4, 2, 5, 7] print max(indexes(a, min(a))) # 3：

示例：

max()

更新; 就完整性而言;如果您本身想要一组具有多个最小值的值的最小索引，那么您只需在表达式的前面换出min() a = [2, 2, 1, 4, 2, 1, 5, 7] print min(indexes(a, min(a))) # 2。所以：

print max(indexes(a, min(a))) # 5

同时

$nom = DB::table('laureats')->pluck('nom');

这通常很方便灵活：）

Answer 3

>>> -min(zip(a, range(0, -len(a), -1)))[1]
3

Answer 4

使用枚举反转列表，其中起始索引为$formatCells = $ws1.Range("A1:W$a") $formatCells.select() $formatCells.font.size=10 $formatCells.Borders.Item($xledgebottom).Weight = $xlThick $formatCells.Borders.Item($xledgetop).Weight = $xlThick $formatCells.Borders.Item($xledgeleft).Weight = $xlThick $formatCells.Borders.Item($xledgeright).Weight = $xlThick $formatCells.Borders.Item($xledgebottom).LineStyle = $xlContinuous $formatCells.Borders.Item($xledgetop).LineStyle = $xlContinuous $formatCells.Borders.Item($xledgeright).LineStyle = $xlContinuous $formatCells.Borders.Item($xledgeleft).LineStyle = $xlContinuous $formatCells = $ws1.Range("A2:W2") $formatCells.select() $formatCells.Borders.Item($xledgebottom).Weight = $xlThin $formatCells.Borders.Item($xledgebottom).LineStyle = $xlContinuous $formatCells = $ws1.Range("A3:W$a") $formatCells.select() $formatCells.Borders.Item($xlinsidehorizontal).LineStyle = $xldot $formatCells.Borders.Item($xlinsidevertical).LineStyle = $xldot $formatCells.Borders.Item($xlinsidehorizontal).Weight = $xlhairline $formatCells.Borders.Item($xlinsidevertical).weight = $xlhairline $formatCells = $ws1.Range("C1:C$a") $formatCells.select() $formatCells.Borders.Item($xledgeright).Weight = $xlThick $formatCells.Borders.Item($xledgeright).LineStyle = $xlContinuous $formatCells = $ws1.Range("F1:F$a") $formatCells.select() $formatCells.Borders.Item($xledgeright).Weight = $xlThick $formatCells.Borders.Item($xledgeright).LineStyle = $xlContinuous $formatCells = $ws1.Range("J1:J$a") $formatCells.select() $formatCells.Borders.Item($xledgeright).Weight = $xlThick $formatCells.Borders.Item($xledgeright).LineStyle = $xlContinuous $formatCells.Borders.Item($xledgeleft).Weight = $xlThick $formatCells.Borders.Item($xledgeleft).LineStyle = $xlContinuous $formatCells = $ws1.Range("N1:N$a") $formatCells.select() $formatCells.Borders.Item($xledgeright).Weight = $xlThick $formatCells.Borders.Item($xledgeright).LineStyle = $xlContinuous $formatCells.Borders.Item($xledgeleft).Weight = $xlThick $formatCells.Borders.Item($xledgeleft).LineStyle = $xlContinuous $formatCells = $ws1.Range("R1:R$a") $formatCells.select() $formatCells.Borders.Item($xledgeright).Weight = $xlThick $formatCells.Borders.Item($xledgeright).LineStyle = $xlContinuous $formatCells.Borders.Item($xledgeleft).Weight = $xlThick $formatCells.Borders.Item($xledgeleft).LineStyle = $xlContinuous $formatCells = $ws1.Range("V1:V$a") $formatCells.select() $formatCells.Borders.Item($xledgeright).Weight = $xlThick $formatCells.Borders.Item($xledgeright).LineStyle = $xlContinuous $formatCells.Borders.Item($xledgeleft).Weight = $xlThick $formatCells.Borders.Item($xledgeleft).LineStyle = $xlContinuous，在生成器中调用next以获取第一个值，从列表长度中减去索引。

Answer 5

遍历枚举列表并使用最大索引：

In [109]: max([ind for ind, val in enumerate(a) if val==min(a)])
Out[109]: 3

Answer 6

找到最小的，然后遍历列表，收集匹配值的索引。

smallest = min(items)
indices = [index for index, value in enumerate(items) if value == smallest]
largest_index = max(indices) # or indices[-1]

如果您的列表非常长，那么您可能需要从后面开始并在到达第一个项目后停止。

largest_index = len(items) - next(index for index, value in \
    enumerate(reversed(items), start=1) if value == smallest)

Answer 7

这可能会：

(len(a) -1 )- a[: : -1].index(min(a))

Answer 8

试试这个：

a=[2,2,4,2,5,7]

minval=min(a)  #min of a

for l in range(len(a)):

  if a[l]==minval:
    index=l
    continue
print index

如何在包含多个最小值的列表中仅查找一个最小值的索引

8 个答案: