我有一个存储过程,返回4列数据
我的问题是它目前以十进制形式返回这些值,并且很难将这些值转换为标准时间,
如何修改此程序以正确返回时间?
USE [Database]
GO
/****** Object: StoredProcedure [dbo].[usp_JobTimeSystem_FetchDepartment] Script Date: 22/05/2015 10:33:23 ******/
SET ANSI_NULLS ON
GO
SET QUOTED_IDENTIFIER ON
GO
ALTER PROCEDURE [dbo].[usp_JobTimeSystem_FetchDepartment]
@FromDate datetime,
@ToDate datetime,
@SystemUserID uniqueidentifier
AS
;WITH cte AS (
SELECT
DATEPART(Year, StartTime) AS YearNumber,
DATEPART(Month, StartTime) AS MonthNumber,
DateName(Month, StartTime) + ' ' + CAST(DatePart(Year, StartTime) AS nvarchar(50)) AS TimePeriod,
DATEADD(day, DATEDIFF(Day, 0, StartTime), 0) AS FromDate,
isnull(DATEDIFF(minute, StartTime, EndTime), 0.0) AS JobTime,
isnull(tblJobWorkLog.ChargeableTime, 0.0) AS ChargeableTime,
WorkLogJobTypeID,
tblJobWorkLog.SystemUserID
FROM
tblJobWorkLog
INNER JOIN tblJob ON tblJobWorkLog.JobID = tblJob.JobID
INNER JOIN tblContact ON tblJob.ContactID = tblContact.ContactID
WHERE
tblJobWorkLog.StartTime >= @FromDate
AND tblJobWorkLog.EndTime <= @ToDate
AND SystemUserID = @SystemUserID
)
Select
FromDate
, SUM(SupportHoursWorked) AS SupportHoursWorked
, SUM(SupportHoursCharged) AS SupportHoursCharged
, SUM(DevelopmentHoursWorked) AS DevelopmentHoursWorked
, SUM(DevelopmentHoursCharged) AS DevelopmentHoursCharged
From (
SELECT
FromDate,
Case when
WorkLogJobTypeID = 'FA5E6979-D228-44B7-A91B-8DDC8DDC709B' -- SUPPORT
OR WorkLogJobTypeID = '3171B295-60E9-4724-95A3-04FA182D7D43' -- QUOTE
OR WorkLogJobTypeID = '52c2691f-ff0a-4263-a440-8a309f868f93' -- HARDWARE
then (SUM(JobTime) / 60.0) else 0.0 end as SupportHoursWorked,
Case when
WorkLogJobTypeID = 'FA5E6979-D228-44B7-A91B-8DDC8DDC709B' -- SUPPORT
OR WorkLogJobTypeID = '3171B295-60E9-4724-95A3-04FA182D7D43' -- QUOTE
OR WorkLogJobTypeID = '52c2691f-ff0a-4263-a440-8a309f868f93' -- HARDWARE
then (SUM(ChargeableTime)) else 0.0 end AS SupportHoursCharged,
Case when
WorkLogJobTypeID = 'D0E910B1-B4BD-430C-AD04-EB4E67946806' -- DATA
OR WorkLogJobTypeID = 'B0BBF362-294D-4262-BED8-EDA7EE74745B' -- EMAILS
OR WorkLogJobTypeID = '1E333ADC-E4F2-4042-8B65-E25F2770D59F' -- WEB DEV
OR WorkLogJobTypeID = 'A445B7CE-E9E4-48E6-B5AA-83C83F045315' -- WEB SUPP
OR WorkLogJobTypeID = '1D83F510-87FA-446E-9337-3D0376210D57' -- SOFTWARE DEV
OR WorkLogJobTypeID = 'B59C1596-E1D0-4118-A805-65208E27AFB5' -- SOFTWARE SUPP
OR WorkLogJobTypeID = 'F44A4B3C-B149-45A8-A9F0-5A57883482FD' -- EMAILS
then (SUM(JobTime) / 60.0) else 0.0 end as DevelopmentHoursWorked,
Case when
WorkLogJobTypeID = 'D0E910B1-B4BD-430C-AD04-EB4E67946806' -- DATA
OR WorkLogJobTypeID = 'B0BBF362-294D-4262-BED8-EDA7EE74745B' -- EMAILS
OR WorkLogJobTypeID = '1E333ADC-E4F2-4042-8B65-E25F2770D59F' -- WEB DEV
OR WorkLogJobTypeID = 'A445B7CE-E9E4-48E6-B5AA-83C83F045315' -- WEB SUPP
OR WorkLogJobTypeID = '1D83F510-87FA-446E-9337-3D0376210D57' -- SOFTWARE DEV
OR WorkLogJobTypeID = 'B59C1596-E1D0-4118-A805-65208E27AFB5' -- SOFTWARE SUPP
OR WorkLogJobTypeID = 'F44A4B3C-B149-45A8-A9F0-5A57883482FD' -- EMAILS
then SUM(ChargeableTime) else 0.0 end as DevelopmentHoursCharged
FROM
cte
GROUP BY
FromDate, WorkLogJobTypeID
) a -- CTETableName
Group by FromDate
ORDER BY
FromDate
全部谢谢
答案 0 :(得分:0)
如果您希望它作为标准日期时间,您可以使用以下表达式:
dateadd(mi,SUM(SupportHoursWorked)*60,'00:00')
如果你想要它“美丽”:
select CONVERT(VARCHAR(8), dateadd(mi,SUM(SupportHoursWorked)*60,'00:00'), 108) 'hh:mi:ss'
答案 1 :(得分:0)
对于Sql Server 2012
及以上:
SELECT timefromparts(SUM(SupportHoursWorked), 0, 0, 0, 0)
一般:
SELECT DATEADD(hh, SUM(SupportHoursWorked), CAST('00:00:00' AS TIME))
修改强>
替换:
Select
FromDate
, SUM(SupportHoursWorked) AS SupportHoursWorked
, SUM(SupportHoursCharged) AS SupportHoursCharged
, SUM(DevelopmentHoursWorked) AS DevelopmentHoursWorked
, SUM(DevelopmentHoursCharged) AS DevelopmentHoursCharged
使用:
Select
FromDate
, DATEADD(mi, SUM(SupportHoursWorked)*60 , CAST('00:00:00' AS TIME)) AS SupportHoursWorked
, DATEADD(mi, SUM(SupportHoursCharged)*60, CAST('00:00:00' AS TIME)) AS SupportHoursCharged
, DATEADD(mi, SUM(DevelopmentHoursWorked)*60, CAST('00:00:00' AS TIME)) AS DevelopmentHoursWorked
, DATEADD(mi, SUM(DevelopmentHoursCharged)*60, CAST('00:00:00' AS TIME)) AS DevelopmentHoursCharged
答案 2 :(得分:0)
我认为这是一个简单的答案。尝试将它们转换为Time数据类型。时间打印出像hh:mm:ss [.nnnnnnn]