Question

我希望有人可以帮助我，我真的很挣扎着我的代码。我正在构建一个简单的Java游戏，你可以使用坐标将X移动到棋盘上的另一个空间，我只是想知道如何在（1,1）处移动它并将其移动到另一个地方。感谢。

package ai;

/**
*
* @author x12388761
*/
import java.util.Scanner;
public class AI {

public static String[][] board = new String[10][10];
public static void addPiece(int x, int y, String r){

    board[x][y] = r;//no need for new String(), board is already made of Strings.
}
public static void showBoard(){
    //it's generally better practice to initialize loop counters in the loop themselves
    for (int row = 0; row < 9; row++)
    {
        System.out.println(" ");
        System.out.println("-------------------");    
        for(int col = 0; col < board[row].length; col++)
        {
            System.out.print("|"); //you're only printing spaces in the spots
            if(board[col][row] == null){
              System.out.print(" ");
            }else{
              System.out.print(board[col][row]);
            }
        }
    }
    System.out.println(" ");
    System.out.println("-------------------");
}
public static void main(String[] args) {
    addPiece(0,0," ");
    addPiece(0,1,"1");
    addPiece(0,2,"2");
    addPiece(0,3,"3");
    addPiece(0,4,"4");
    addPiece(0,5,"5");
    addPiece(0,6,"6");
    addPiece(0,7,"7");
    addPiece(0,8,"8");
    addPiece(1,0,"1");
    addPiece(2,0,"2");
    addPiece(3,0,"3");
    addPiece(4,0,"4");
    addPiece(5,0,"5");
    addPiece(6,0,"6");
    addPiece(7,0,"7");
    addPiece(8,0,"8");
    addPiece(1,1,"X");  
    addPiece(8,8,"O");
    showBoard(); 
    Scanner myScan = new Scanner(System.in);


    System.out.println("Would you like to go first? Yes or No");
    String goFirst = myScan.nextLine();

    if(goFirst.equals("yes") || goFirst.equals("Yes") || goFirst.equals("YES")) {
        System.out.println("You are X! Please enter the coordinates of your first move");
        String coordinate = myScan.nextLine();
        String[] parts = coordinate.split(",");


        String x = parts[0];
        String y = parts[1];



        System.out.println("Moving to (" + x +","+ y +")");

        }

    if(goFirst.equals("no") || goFirst.equals("No") || goFirst.equals("NO")) {
        System.out.println("You are O! The computer will make the first move.");

        }



}


}

Answer 1

/** Move 1 to 2, 1 is empty after move */
public static void move(int x1, int y1, int x2, int y2) {
     board[x2][y2] = board[x1][y1];
     board[x1][y1] = " ";
}

这是有效的，因为2设置为1，然后1设置为空。这没有检查以确保2为空或1有一块。如果你想检查一下，你需要使用它：

/** Move 1 to 2, 1 is empty after move */
public static void move(int x1, int y1, int x2, int y2) {
    if (!board[x1][y1].equals(" ") && board[x2][y2].equals(" ")) {// if 1 is not empty
                                                      // and 2 is empty
        board[x2][y2] = board[x1][y1];
        board[x1][y1] = " ";
    }
}

加分：改进代码的方法

当您询问用户他是否想先行时，您使用String.equals检查输入，这是一个艰难的方法。在这种情况下，您应该使用String.equalsIgnoreCase，即goFirst.equalsIgnoreCase("yes")。

在show board方法中，您可以使用：

 System.out.println(" ");
 System.out.println("-------------------");

可以使用特殊换行符println加入两个\n，如下所示：

System.out.println("\n-------------------");

Answer 2

判断用户输入是或否，您可以使用equalsIgnoreCase方法。此方法忽略大写或小写。如下所示：

String upper = "YES";
String lower = "yes";
upper.equalsIgnoreCase(lower);// true

如果String lower =＆＃34; YeS＆＃34 ;;结果也一样。

移动＆＃34; X＆＃34;到不同的位置

2 个答案: