Question

我试图弄清楚如何通过SVG文件中的id访问特定元素。我正在使用lxml的python库来解析文件，但它总是空的。这是我用来访问元素的python脚本：

#!/usr/bin/env python

from lxml import etree
XHTML_NAMESPACE = "http://www.w3.org/2000/svg"
XHTML = "{%s}" % XHTML_NAMESPACE
NSMAP = {None : XHTML_NAMESPACE}

root = etree.parse("temp.svg")
textid = "text1274"
path = ".//text[@id='" + textid + "']/title"
name = root.findtext(path=path, namespaces=NSMAP)
print name

结果始终为空字符串（＆＃39;无＆＃39;），但没有错误。它相信它找到了我想要的东西，但我想要的是元素文本（应该是＆＃34; Wei，771 - 661BCE。＆＃34;）。以下是有罪的SVG文件：

<?xml version="1.0" encoding="UTF-8" standalone="no"?>

<svg
   xmlns:dc="http://purl.org/dc/elements/1.1/"
   xmlns:cc="http://creativecommons.org/ns#"
   xmlns:rdf="http://www.w3.org/1999/02/22-rdf-syntax-ns#"
   xmlns:svg="http://www.w3.org/2000/svg"
   xmlns="http://www.w3.org/2000/svg"
   xmlns:xlink="http://www.w3.org/1999/xlink"
   xmlns:sodipodi="http://sodipodi.sourceforge.net/DTD/sodipodi-0.dtd"
   xmlns:inkscape="http://www.inkscape.org/namespaces/inkscape"
   version="1.1"
   xml:space="preserve"
   viewBox="0 0 54001 32400"
   id="svg2"
   inkscape:version="0.91 r"
   sodipodi:docname="china700BC.svg"><sodipodi:namedview
   pagecolor="#ffffff"
   bordercolor="#666666"
   borderopacity="1"
   objecttolerance="10"
   gridtolerance="10"
   guidetolerance="10"
   inkscape:pageopacity="0"
   inkscape:pageshadow="2"
   inkscape:window-width="1366"
   inkscape:window-height="692"
   id="namedview2468"
   showgrid="false"
   inkscape:zoom="0.016419753"
   inkscape:cx="17689.896"
   inkscape:cy="17739.986"
   inkscape:window-x="0"
   inkscape:window-y="24"
   inkscape:window-maximized="1"
   inkscape:current-layer="svg2" />
<defs
   id="defs4">
<filter
   id="blur2">
<feGaussianBlur
   id="feGaussianBlur7"
   result="blur"
   stdDeviation="2"
   in="SourceGraphic" /> 
</filter>
<filter
   id="blur4">
<feGaussianBlur
   id="feGaussianBlur10"
   result="blur"
   stdDeviation="4"
   in="SourceGraphic" /> 
</filter>
<filter
   id="blur8">
<feGaussianBlur
   id="feGaussianBlur13"
   result="blur"
   stdDeviation="8"
   in="SourceGraphic" /> 
</filter>
<filter
   id="blur16">
<feGaussianBlur
   id="feGaussianBlur16"
   result="blur"
   stdDeviation="16"
   in="SourceGraphic" /> 
</filter>
<filter
   id="blur32">
<feGaussianBlur
   id="feGaussianBlur19"
   result="blur"
   stdDeviation="32"
   in="SourceGraphic" /> 
</filter>
<filter
   id="blur64">
<feGaussianBlur
   id="feGaussianBlur22"
   result="blur"
   stdDeviation="64"
   in="SourceGraphic" /> 
</filter>

</defs> 
&gt;

<g
   stroke-linecap="round"
   stroke-linejoin="round"
   stroke-miterlimit="7"
   stroke-width="14"
   fill="none"
   filter="url(#blur2)"
   id="fntr">
<ellipse
   id="ellipse381"
   fill="white"
   stroke="white"
   ry="1"
   rx="1"
   cy="0"
   cx="0" />
<ellipse
   id="ellipse383"
   fill="white"
   stroke="white"
   ry="1"
   rx="1"
   cy="32400"
   cx="54001" />
<ellipse
   fill="#FEBADE"
   ry="1"
   rx="1"
   cy="24759"
   cx="48948"
   id="295286-dummy" />
</g>

<g
   text-anchor="middle"
   id="regn">
</g>
<g
   text-anchor="middle"
   id="cultr">
</g>
<g
   text-anchor="middle"
   id="peopl">
</g>
<g
   font-style="italic"
   text-anchor="middle"
   id="tribe">
</g>

<text
   id="text455"
   x="30542.088"
   y="16248.173"
   font-size="20"
   style="font-weight:normal;font-size:233.01080322px;text-anchor:middle"><title
   id="title457">Chen.</title>Chen</text>

<text
   id="text1274"
   x="28689.652"
   y="12753.011"
   font-size="28"
   style="font-weight:normal;font-size:326.21511841px;text-anchor:middle"><title
   id="title1276">Wei, 771 - 661BCE.</title>Wei</text>

   <script
   id="script2466">
      function LoadHandler(event) 
      {
         new Title(event.getTarget().getOwnerDocument(), 810);
      }
   </script>
</svg>

我发现我可以通过删除第8行来消除错误，以＆＃34; xmlns = ...＆＃34;开头。（这是名称空间声明）。但是，由于我获取此文件的性质，我无法永久删除此行（并且可能不应该）。有没有办法（比如正确指定命名空间）我可以得到预期的输出而不必编辑XML？

非常感谢

Answer 1

将默认命名空间映射到None前缀对我来说也不起作用。但是，您可以将其映射到普通字符串前缀并在xpath中使用该前缀，其余代码可以正常工作：

from lxml import etree
XHTML_NAMESPACE = "http://www.w3.org/2000/svg"
XHTML = "{%s}" % XHTML_NAMESPACE
NSMAP = {'d' : XHTML_NAMESPACE}  # map default namespace to prefix 'd:'

root = etree.parse("temp.svg")
textid = "text1274"
path = ".//d:text[@id='" + textid + "']/d:title" # use registered prefix in xpath
name = root.findtext(path=path, namespaces=NSMAP)
print name

Python：在lxml.etree路径

1 个答案: