注意:我正在处理我事先不知道其结构的xml文件,因此我无法使用XPath 这是我的xml文件的一个例子:
<?xml version="1.0" encoding="ISO-8859-1" standalone="yes" ?>
<HWData>
<Header time="2013-05-29T13:39:34" uploaded="true" version="1.0" />
<NE vendorName="Nokia Siemens Networks" NEId="WBTS-431">
<EQHO vendorName="Nokia Siemens Networks" equipmentHolderId="173" >
<UNIT vendorName="N" unitId="16" />
<UNIT vendorName="NOKIA SIEMENS NETWORKS" unitId="225" />
</EQHO>
<EQHO vendorName="NSN" equipmentHolderId="40192" >
<UNIT vendorName="AR" unitId="40267" />
</EQHO>
</NE>
<NE vendorName="Nokia Siemens Networks" NEId="WBTS-261">
<EQHO vendorName="Nokia Siemens Networks" equipmentHolderId="132" >
<EQHO vendorName="Nokia Siemens Networks" equipmentHolderId="132-1">
<UNIT vendorName="NN" unitId="1621" />
</EQHO>
</EQHO>
</NE>
</HWData>
我想知道我是否可以使用例如节点名称&#34; NE&#34;和属性值NEID =&#34; WBTS-261&#34;结果就是这个洞!
结果预期:
<NE vendorName="Nokia Siemens Networks" NEId="WBTS-261">
<EQHO vendorName="Nokia Siemens Networks" equipmentHolderId="132" >
<EQHO vendorName="Nokia Siemens Networks" equipmentHolderId="132-1">
<UNIT vendorName="NN" unitId="1621" />
</EQHO>
</EQHO>
</NE>
有人可以让我以正确的方式做任何例子,想法或建议将不胜感激..谢谢
答案 0 :(得分:1)
将此方法用作字符串:
public static String NodeToString(String file,String moid) throws SAXException, IOException, ParserConfigurationException{
String stringNode="";
InputStream in = new ByteArrayInputStream(file.getBytes("ISO-8859-1"));
Document doc = DocumentBuilderFactory.newInstance().newDocumentBuilder().parse(in);
NodeList nodeList = doc.getElementsByTagName("*");
for (int i = 0; i < nodeList.getLength(); i++) {
if(nodeList.item(i) instanceof Element && ((Element)nodeList.item(i)).getAttribute("MOID").equalsIgnoreCase(moid)){
try
{
// Set up the output transformer
TransformerFactory transfac = TransformerFactory.newInstance();
Transformer trans = transfac.newTransformer();
trans.setOutputProperty(OutputKeys.OMIT_XML_DECLARATION, "yes");
trans.setOutputProperty(OutputKeys.INDENT, "yes");
// Print the DOM node
StringWriter sw = new StringWriter();
StreamResult result = new StreamResult(sw);
DOMSource source = new DOMSource(nodeList.item(i));
trans.transform(source, result);
stringNode = sw.toString();
//System.out.println(xmlString);
}
catch (TransformerException e)
{
e.printStackTrace();
}
}
}
return stringNode;
}