Question

无论我做什么，CSV文件的输出都是空白的。请告诉我我做错了什么。我只需要找出输出没有到达CSV文件的原因。

$servers = Get-Content "C:\temp\servers.txt"
foreach ($Server in $servers) {
    Get-IPAddress -ComputerName $servers -IPV4only
} 
Select-Object Name, IP | Export-CSV c:\temp\final.txt

函数Get-IPAddress的实现如下：

function global:Get-IPAddress {
  #Requires -Version 2.0
  [CmdletBinding()]
  Param (
    [Parameter(Position=1,
              ValueFromPipeline=$true,
              ValueFromPipelineByPropertyName=$true)]
    [String[]]$ComputerName = $env:COMPUTERNAME,
    [Switch]$IPV6only,
    [Switch]$IPV4only
  )#End Param

  Begin {
    Write-Verbose "`n Checking IP Address . . .`n"
    $i = 0
  }#Begin

  Process {
    $ComputerName | ForEach-Object {
      $HostName = $_

      Try {
        $AddressList = @(([net.dns]::GetHostEntry($HostName)).AddressList)
      } Catch {
        "Cannot determine the IP Address on $HostName"
      }

      If ($AddressList.Count -ne 0) {
        $AddressList | ForEach-Object {
          if ($IPV6only) {
            if ($_.AddressFamily -eq "InterNetworkV6") {
              New-Object psobject -Property @{
                IPAddress    = $_.IPAddressToString
                ComputerName = $HostName
              } | Select ComputerName,IPAddress
            }
          }
          if ($IPV4only) {
            if ($_.AddressFamily -eq "InterNetwork") {
              New-Object psobject -Property @{
                IPAddress    = $_.IPAddressToString
                ComputerName = $HostName
              } | Select ComputerName,IPAddress
            }
          }
          if (!($IPV6only -or $IPV4only)) {
            New-Object psobject -Property @{
              IPAddress    = $_.IPAddressToString
              ComputerName = $HostName
            } | Select ComputerName,IPAddress
          }
        }#Foreach-Object(IPAddress)
      }#IF
    }#Foreach-Object(ComputerName)
  }#Process
}#Get-IPAddress

Answer 1

您没有提供任何可供选择的内容（您在Get-IPAddress循环中运行foreach，但输出未传递到Select-Object cmdlet中。此外，您的函数生成具有ComputerName属性的对象，但您尝试选择属性Name。

将您的代码更改为：

Get-Content 'C:\temp\servers.txt' | ForEach-Object {
    Get-IPAddress -ComputerName $servers -IPV4only
} | Select-Object ComputerName, IP | Export-Csv 'c:\temp\final.txt' -NoType

作为旁注，您可能希望将开关-IPV4only和-IPV6only互斥，方法是将它们放入不同的参数集中：

[CmdletBinding(DefaultParameterSetName='all')]
Param (
  [Parameter(Position=1,
            ValueFromPipeline=$true,
            ValueFromPipelineByPropertyName=$true)]
  [String[]]$ComputerName = $env:COMPUTERNAME,
  [Parameter(ParameterSetName='v6')]
  [Switch]$IPV6only,
  [Parameter(ParameterSetName='v4')]
  [Switch]$IPV4only
)

Answer 2

查看您的代码段，两个语句（foreach(...)构造和Select-Object|Export-Csv表达式）完全断开连接。

将foreach内的表达式的输出分配给变量，并将其输出到Select-Object而不是

$servers = Get-Content "C:\temp\servers.txt"
$Output = foreach ($Server in $Servers)
{
    Get-IPAddress -ComputerName $server -IPV4only |Select IP,@{Name="Name";Expression={$server}}
}
$Output | Select-Object Name, IP | Export-CSV c:\temp\final.txt

CSV文件为空

2 个答案: