Question

我希望将列amount按自定义的每周日期范围分组，即每个星期一到星期日。

我的数据看起来像这样

date              weekday         amount
---------------|--------------|---------------
2015-03-01        sun              40
2015-03-02        mon              670
2015-03-03        tue              430
2015-03-04        wed              70
2015-03-05        thu              220
2015-03-06        fri              7
2015-03-07        sat              780
2015-03-08        sun              43
2015-03-09        mon              10
2015-03-10        tue              200
2015-03-11        wed              30
2015-03-12        thu              40
2015-03-13        fri              500
2015-03-14        sat              80
2015-03-15        sun              20
2015-03-16        mon              30
2015-03-17        tue              90
2015-03-18        wed              50
2015-03-19        thu              50
2015-03-20        fri              60
2015-03-21        sat              810
2015-03-22        sun              30
2015-03-23        mon              50

等，

等

我希望实现这样的目标

amount         week
-----------|--------------------------------|---
2200        2015-03-02 - 2015-03-08
910         2015-03-09 - 2015-03-15
1120        2015-03-16 - 2015-03-22

或者，如果可能的话，这样会更好（如果没有，那么我只需将上述示例正则表示为新列）

amount         date_start         date_end
-----------|------------------|----------------|---
2200           2015-03-02         2015-03-08
910            2015-03-09         2015-03-15
1120           2015-03-16         2015-03-22

Answer 1

预期的结果不会如下吗？如果没有，为什么不......

+------------+--------+
| date       | amount |
+------------+--------+
| 2015-03-01 |     40 |40
+------------+--------+
| 2015-03-02 |    670 |
| 2015-03-03 |    430 |
| 2015-03-04 |     70 |
| 2015-03-05 |    220 |
| 2015-03-06 |      7 |
| 2015-03-07 |    780 |
| 2015-03-08 |     43 |2220
+------------+--------+
| 2015-03-09 |     10 |
| 2015-03-10 |    200 |
| 2015-03-11 |     30 |
| 2015-03-12 |     40 |
| 2015-03-13 |    500 |
| 2015-03-14 |     80 |
| 2015-03-15 |     20 |880
+------------+--------+
| 2015-03-16 |     30 |
| 2015-03-17 |     90 |
| 2015-03-18 |     50 |
| 2015-03-19 |     50 |
| 2015-03-20 |     60 |
| 2015-03-21 |    810 |
| 2015-03-22 |     30 |1120
+------------+--------+
| 2015-03-23 |     50 |50
+------------+--------+

假设我是对的，那么：

SELECT MIN(date) start
     , MAX(date) end
     , SUM(amount) total 
  FROM my_table 
 GROUP 
    BY YEARWEEK(date,1);
+------------+------------+-------+
| start      | end        | total |
+------------+------------+-------+
| 2015-03-01 | 2015-03-01 |    40 |
| 2015-03-02 | 2015-03-08 |  2220 |
| 2015-03-09 | 2015-03-15 |   880 |
| 2015-03-16 | 2015-03-22 |  1120 |
| 2015-03-23 | 2015-03-23 |    50 |
+------------+------------+-------+

Answer 2

您可以尝试以下查询： -

SELECT SUM(amount) AS total, CONCAT(date, ' - ', date + INTERVAL 6 DAY) AS week 
FROM Your_Table 
GROUP BY WEEK(date, 1) 
ORDER BY WEEK(date, 1)

按自定义数据范围分组和求和

2 个答案: