Question

非常简单的问题，但如何从＆＃34;从List＆＃34;

中选择启动脚本

例如：

set issueList to {"1", "2", "2", "4"}

set selectedIssue to {choose from list issueList}

if selectedIssue is {"1"} then
    display dialog "ok" buttons {"1"} default button 1
else if selectedIssue is {"Holds Charge"} then
    -- do nothing
    display dialog "ok" buttons {"2"} default button 1
else if selectedIssue is {"2"} then
    -- do nothing
    display dialog "ok" buttons {"3"} default button 1
else if selectedIssue is {"3"} then
    -- do nothing   
    display dialog "ok" buttons {"4"} default button 1
end if

当我点击列表中的元素，通知开始（或任何其他脚本）时，我在此脚本中的预期，但我没有结果。

干杯

Answer 1

通知会返回{{＆＃34; 1＆＃34;}}，而非{＆＃34; 1＆＃34;}。将您的代码更改为

if item 1 of selectedIssue is {"1"} then

等等，它应该工作。

Answer 2

你好，我也遇到了同样的问题，但是我用这样的代码解决了：

set mailList to {"One","Two","Three","Four"}
set mailType to choose from list mailList

if item 1 of mailType is "One" then
    display dialog mailType 
else if item 1 of mailType is "Two" then
    display dialog mailType 
else if item 1 of mailType is "Three" then
    display dialog mailType 
else if item 1 of mailType is "Four" then
    display dialog mailType 
end if

AppleScript从列表中选择

2 个答案: