Question

我注意到从输入表单插入带有mysqli程序样式的数据时，我使用mysqli，所以当我从mysql将代码更改为mysqli时，它有很多错误和注意事项，其中一个像：undefined variable：gambar in .. 。（我的本地xampp目录）在第43行。数据和图像成功存储到数据库，但是当我没有插入图像时，它会显示通知。这是我的代码：

<?php session_start();
include "../config.php";
include "judul_seo.php";

$id           = mysql_real_escape_string($_POST['id']);
$judul_event  = mysql_real_escape_string($_POST['judul_event']);
$judul_seo    = judul_seo($judul_event);
$keywords     = mysql_real_escape_string($_POST['keywords']);
$caption      = mysql_real_escape_string($_POST['caption']);
$deskripsi    = mysql_real_escape_string($_POST['deskripsi']);
if (empty($id))
{              
  die("Isikan ID!"); //Berhenti dan munculkan pesan jika ID tidak diisi
} 
elseif(empty($judul_event))
{
  die("Isikan Judul Event!");
}
else
{
  if (!empty($_FILES["gambar"]["tmp_name"]))
  {
    $namafolder = "../images/event/";  //tempat menyimpan file
    $jenis_gambar =$_FILES['gambar']['type'];

    if($jenis_gambar=="image/jpeg"  || $jenis_gambar=="image/jpg" || $jenis_gambar=="image/gif"  || $jenis_gambar=="image/png")
    {           
      $gambar = $namafolder . basename($_FILES['gambar']['name']);       
      if  (!move_uploaded_file($_FILES['gambar']['tmp_name'], $gambar))
      { 
        die("Gambar gagal dikirim"); 
      }
   } 
   else  
   { 
     die("Jenis gambar yang anda kirim salah. Harus .jpg .gif .png"); 
   }
 }
 //end if cek file upload

 $sql = "INSERT INTO eventbl(id,judul_event,judul_seo,keywords,caption,deskripsi,gambar) 
       VALUES ('$id','$judul_event','$judul_seo','$keywords','$caption','$deskripsi','$gambar')";
  if (mysqli_query($conn, $sql)) 
  {
    echo "<script>alert('Insert data berhasil! Klik ok untuk melanjutkan');location.replace('event.php')</script>";
  } 
    else 
    {
     echo "Error updating record: " . mysqli_error($conn);
    }
}
?>

judul_seo script:
<?php
function judul_seo($string)
{
  $c = array (' ');
  $d = array ('-','/','\\',',','.','#',':',';','\'','"','[',']','{','}',')','(','|','`','~','!','@','%','$','^','&','*','=','?','+');
  $string = str_replace($d, '', $string);
  $string = strtolower(str_replace($c, '-', $string));
  return $string;
 }
 ?>

任何帮助都会非常有帮助。感谢

Answer 1

使用isset函数检查文件是否已过帐例如： -

if (isset($_FILES["gambar"]["tmp_name"]) && !empty($_FILES["gambar"]["tmp_name"])){}

希望这会对你有所帮助

Answer 2

在这行语句之前定义一个空变量，如下所示：

$gambar = '';
if (empty($id))
{              
   die("Isikan ID!"); //Berhenti dan munculkan pesan jika ID tidak diisi
}

PHP MYSQLI程序样式上的未定义变量

2 个答案: