Question

我是SAS新手并拥有一个名为ORIG_DATA的简单数据集，我需要根据该数据集创建一个新的数据集摘要，按照Day_ID显示按Salesman_ID计算的总数

本质上，SUMMARY输出应该如下所示，其中数字是总数的总和。

Salesman_ID|Day_1|Day_2
A          |30   |40
B          |60   |0
C          |20   |70

在SQL中，我做

Select salesman_id, 
sum(case when day_id=1 then total else 0 end) as day_1,
sum(case when day_id=2 then total else 0 end) as day_2
from ORIG_DATA group by salesman_id

但是对于这个问题，我不允许使用proc sql。我怎么能在SAS中做到这一点？哈文目前最模糊。对不可格式的道歉

ORIG_DATA如下

Day_ID|Salesman_ID|Other_field|total
1     |A          |R000       |10
1     |A          |R002       |20
2     |A          |R000       |10
2     |A          |R004       |30
1     |B          |R002       |20
1     |B          |R000       |40
1     |B          |R004       |0
2     |C          |R003       |40
2     |C          |R004       |10
1     |C          |R002       |20
2     |C          |R002       |20

Answer 1

您可以通过简单的数据步骤解决问题，请参阅下面的代码。您需要先对数据进行排序，然后指示数据与您在新组开始时将day_1和day_2重置为零的组一起使用，并输出到上次观察时的数据集。

如果您有任何疑问，请与我们联系。

<a style="color:white" id="randomNo">Hello</a>;

Answer 2

这个怎么样？我不知道每other_field每salesman_id只有day_id个data ORIG_DATA ; input Day_ID Salesman_ID $ Other_field $ total ; cards ; 1 A R000 10 1 A R002 20 2 A R000 10 2 A R004 30 1 B R002 20 1 B R000 40 1 B R004 0 2 C R003 40 2 C R004 10 1 C R002 20 2 C R002 20 ;run;个记录。以下内容适用于1到n条记录：

输入数据：

proc sort data=ORIG_DATA ;
  by salesman_id day_id ;
proc transpose data=ORIG_DATA out=D1 ;
  by salesman_id  day_id ;
  var total ;
run ;

data D2 ;
  set D1 ;
  array D(*) col: ;
  _name_=cats('day_',day_id) ;
  by salesman_id day_id;
  total=sum(of D(*)) ; 
run ;

proc transpose data=D2 out=SUMMARY(drop=_name_) name=_name_;
  by salesman_id  ;
  var total ;
run ;

*Add zeros for missing values ;
data SUMMARY ;
  set SUMMARY ;
  array days day_: ;
  do over days ;
    if missing(days) then days=0;
  end ;
run ;

转置，求和并转置回来：

{{1}}

Answer 3

其他方法：

proc summary data=orig_data nway;
class day_id salesman_id;
var total;
output out=sum(drop=_:) sum=;
run;

proc sort data=sum;
by salesman_id day_id;
run;

proc transpose data=sum out=want(drop=_name_) prefix=day_;
by salesman_id;
var total;
run;

Answer 4

类似的一个：

proc sort data = orig_data(drop = Other_field);
by salesman_id day_id;
run;

data test (drop = total);
  retain salesman_id day_id;
    set orig_data ;
  by salesman_id day_id notsorted;

  if first.day_id then sum = total;
  else sum + total;

  if last.day_id then output;

run;

proc transpose data = test out = t(drop=_:) prefix = day_id_;
by salesman_id;
id day_id;
var sum;
run;

sas条件总和到新的领域

4 个答案: