Question

我正在使用Angularjs开发一个网站，我是初学者。所以我有一个组合框。选择一个选项后，它会调用一个方法，并应在Scope变量中加载值并进行更新。这是我的代码。

if(array[i].text.indexOf('hello') > -1){
    //Rest of your code
}

和HTML部分

var app = angular.module('myApp', []);
app.controller('myCtrl',  function ($scope, $http) {


    $scope.castVals = {};

    $http.get("http://localhost:8083/project/php/get_recipies.php")
    .success(function (response) {
        $scope.recipies = response.records;
        $scope.selectedItem = null;

    });

    $scope.selectedItemChanged = function (val) {

        $http.get("http://localhost:8083/project/php/get_cast_param.php?v="+val)
                    .success(function (response) {
                        $scope.castVals = response;

         });

    };

});

由于阿什拉夫

Answer 1

您不需要将所选值传递给selectedItemChange方法，因为从范围变量获取它在控制器上更安全。

  <select id="soflow" ng-model="selectedItem" ng-change="selectedItemChanged()">
                    <option ng-repeat="rec in recipies" value="{{rec.Rezept_Nr}}">{{rec.Rezept_Bez}}</option>
                </select>

//控制器

var app = angular.module('myApp', []);

app.controller('myCtrl',  function ($scope, $http) {


$scope.castVals = {};
$scope.selectedItem;

$http.get("http://localhost:8083/project/php/get_recipies.php")
.success(function (response) {
    $scope.recipies = response.records;
    $scope.selectedItem = null;

});

$scope.selectedItemChanged = function () {

    $http.get("http://localhost:8083/project/php/get_cast_param.php?v="+ $scope.selectedItem)
                .success(function (response) {
                    $scope.castVals = response;

     });

};

});

Angularjs在select上显示数据

1 个答案: