Question

如何删除数组中间的项目？我试过这个：

Public Sub RemoveArrayElement(AryVar() As Object, ByVal RemoveWhich As Long)
Dim byteLen As Byte    
byteLen = 4

If RemoveWhich < UBound(AryVar) Then
    CopyMemory ByVal VarPtr(AryVar(RemoveWhich)), ByVal _
        VarPtr(AryVar(RemoveWhich + 1)), (byteLen) * _
        (UBound(AryVar) - RemoveWhich)
End If

If UBound(AryVar) = LBound(AryVar) Then
    Erase AryVar
Else
    ReDim Preserve AryVar(UBound(AryVar) - 1)
End If
End Sub

但是当我从aryvar检索项目时，它会返回Nothing。

Answer 1

和另一种方法：

'1 form with:
'  1 command button: name=Command1

Option Explicit

Private Sub Command1_Click()
  Dim intIndex As Integer
  'dim an array with undefined boundaries
  Dim intArray() As Integer
  'set boundaries
  ReDim intArray(10) As Integer
  'fill array with values
  For intIndex = 0 To 10
    intArray(intIndex) = intIndex * intIndex
  Next intIndex
  'show the data from the initial array
  ShowArray intArray
  'remove the 6th item (index=5)
  intArray = RemoveItem(5, intArray)
  'show the data of the resulting array (with the 6h item removed)
  ShowArray intArray
End Sub

Private Function RemoveItem(intItem As Integer, intSrc() As Integer) As Integer()
  Dim intIndex As Integer
  Dim intDest() As Integer
  Dim intLBound As Integer, intUBound As Integer
  'find the boundaries of the source array
  intLBound = LBound(intSrc)
  intUBound = UBound(intSrc)
  'set boundaries for the resulting array
  ReDim intDest(intLBound To intUBound - 1) As Integer
  'copy items which remain
  For intIndex = intLBound To intItem - 1
    intDest(intIndex) = intSrc(intIndex)
  Next intIndex
  'skip the removed item
  'and copy the remaining items, with destination index-1
  For intIndex = intItem + 1 To intUBound
    intDest(intIndex - 1) = intSrc(intIndex)
  Next intIndex
  'return the result
  RemoveItem = intDest
End Function

Private Sub ShowArray(intArray() As Integer)
  Dim intIndex As Integer
  'print all items to the form to show their value
  For intIndex = LBound(intArray) To UBound(intArray)
    Print "Item " & CStr(intIndex) & " : " & CStr(intArray(intIndex))
  Next intIndex
  'print an empty line to separate the arrays in displaying
  Print
End Sub

差异：

返回数组而不是传递byref
使用一个临时数组，该数组调暗到正确的大小而不是最后的redim保存
复制保留相同索引的项目，只移动删除项目后的项目

Answer 2

有一种不同的方法，然后是你正在上面采用的方法，但是你不能只是将所有值向下移动并随后缩小数组吗？

例如：

Public Sub RemoveArrayElement(ByRef AryVar() As Object, ByVal RemoveWhich As Long)
    If UBound(AryVar) > 0 Then
        For i As Integer = LBound(AryVar) To UBound(AryVar) - 1
            If i >= removeWhich Then
                    AryVar(i) = AryVar(i + 1)
            End If
        Next
        ReDim Preserve AryVar(UBound(AryVar) - 1)
    End If
End Sub

Answer 3

那么这段代码可能对您有所帮助。

Dim remove_place As Integer
Dim ar() As Integer
Dim n As Integer
n = 10
ReDim ar(n)                     'Initial size of an array
remove_place = Val(Text1.Text)  'This is the position to be deleted
For i = remove_place To n - 1
ar(i) = ar(i + 1)               'This loop will shift array position one    place   to the left. This way the number at your position will be replaced by the next number.
Next
ReDim Preserve ar(n - 1)        'I guess you know what it means.

将其置于任何事件程序之下。

从数组中删除项目

3 个答案: