如何在HiveQL中有效实现GROUP BY组合？

Question

例如，我有下表名为Roll：

ID    Name    Address
---------------------
01    Lily    NewYork
02    Lucy    NewYork
03    Lucy    NewYork

我希望获得COUNT（1）GROUP BY组合名称和地址：

SELECT Name, Address, COUNT(1) FROM Roll GROUP BY Name, Address
+
SELECT Name, COUNT(1) FROM Roll GROUP BY Name
+
SELEC Address, COUNT(1) FROM Roll GROUP BY Address
+
SELECT COUNT(1) FROM Roll

以下SQL可以实现我的想法，'##'代表'GROUP BY NONE'：

SELECT Name, Address, COUNT(1) FROM (
SELECT Name, Address FROM Roll
UNION ALL
SELECT '##', Address FROM Roll
UNION ALL
SELECT Name, '##' FROM Roll
UNION ALL
SELECT '##', '##' FROM Roll) t
GROUP by Name, Address;

结果：

+------+---------+----------+
| Name | Address | COUNT(1) |
+------+---------+----------+
| ##   | ##      |        3 |
| ##   | NewYork |        3 |
| Lily | ##      |        1 |
| Lily | NewYork |        1 |
| Lucy | ##      |        2 |
| Lucy | NewYork |        2 |
+------+---------+----------+

除了上面的方法之外，更有效的方法是实现吗？

感谢。

Answer 1

你正在寻找小计吗？如果是这样，可以通过分组集和立方体/汇总来实现。 check this wiki about grouping

Answer 2

SELECT coalesce(Name,"##"), coalesce(Address,"##"), count(1)
FROM ROLL
GROUP BY Name, Address with cube;

我想这就是你要找的东西：）