如何删除一行，其中包含以空格开头的字符串？

Question

我的数据集如下所示

John
Tally
 mac
hero

我想删除以＆＃34开头的字符串; ＆＃34;

所以结果变量是

John
Tally
hero

我用过

library(stringr)
which(startsWith(names[,1]," "))

获取行＆＃34; ＆＃34;

请帮我以任何有效的方式删除它？

Answer 1

regex和grepl的一种方式：

vec <- c('John',
         'Tally',
         ' mac',
         'hero')

 #grepl returns TRUE if there is a match.
 #'^ ' is regex for 'starting with space'
  > vec[!grepl('^ ', vec)]
[1] "John"  "Tally" "hero" 

或者根据@NealFultz的评论：

> vec[grep('^ ', vec, invert=TRUE)]
[1] "John"  "Tally" "hero"

> grep('^ ', vec, invert=TRUE, value=TRUE)
[1] "John"  "Tally" "hero" 

或者如果您想使用startsWith：

library(gdata)
#notice the minus sign below just before which
> vec[-which(startsWith(vec," "))]
[1] "John"  "Tally" "hero" 

或简单地（根据@Gregor的评论）：

> vec[!startsWith(vec, " ")]
[1] "John"  "Tally" "hero" 

Answer 2

使用stringr：

> vec[!str_detect(vec, "^\\s")]
# [1] "John"  "Tally" "hero" 

使用stringi：

> vec[!stri_detect(vec, regex = "^\\s")]
# [1] "John"  "Tally" "hero"