Question

我正在尝试将用户提供的用户名存储在变量中，然后使用该用户名通过ssh登录服务器。

这似乎有效

amit@sharknado:~$ read -p "username: " username; ssh -l $username localhost
username: foobartest
foobartest@localhost's password:

但是，当我对/bin/sh -c执行相同操作时，$username似乎没有存储？

amit@sharknado:~$ /bin/sh -c "read -p \"username: \" username; ssh -l $username localhost"
username: foobar
usage: ssh [-1246AaCfgKkMNnqsTtVvXxYy] [-b bind_address] [-c cipher_spec]
           [-D [bind_address:]port] [-E log_file] [-e escape_char]
           [-F configfile] [-I pkcs11] [-i identity_file]
           [-L [bind_address:]port:host:hostport] [-l login_name] [-m mac_spec]
           [-O ctl_cmd] [-o option] [-p port]
           [-Q cipher | cipher-auth | mac | kex | key]
           [-R [bind_address:]port:host:hostport] [-S ctl_path] [-W host:port]
           [-w local_tun[:remote_tun]] [user@]hostname [command]
amit@sharknado:~$

Answer 1

发现我只需要使用-c参数的单引号而不是双引号

amit@sharknado:~$ /bin/sh -c 'read -p "username: " username; ssh -l $username localhost'
username: testfoo
testfoo@localhost's password:

/ bin / sh -c＆＃34; read var; echo $ var＆＃34;没有使用价值阅读

1 个答案: