Question

我在Android中使用ColorPicker。当我从ColorPicker设置所需的颜色时，它可以正常工作。但是当我退出并再次重新启动activity时，我的颜色恢复到默认状态。我已经在两周内解决了这个问题，并尝试了SharedPreferences的每一件事！这是我的代码：

MainActivity.java：

package com.example.project;

import yuku.ambilwarna.AmbilWarnaDialog;
import yuku.ambilwarna.AmbilWarnaDialog.OnAmbilWarnaListener;
import android.app.Activity;
import android.content.Intent;
import android.content.SharedPreferences;
import android.content.SharedPreferences.Editor;
import android.os.Bundle;
import android.view.View;
import android.widget.AdapterView;
import android.widget.AdapterView.OnItemClickListener;
import android.widget.ArrayAdapter;
import android.widget.ListView;
import android.widget.RelativeLayout;

public class Preferences extends Activity {

    String[] pref_list = { "Background Color", "Background Wallpaper" };
    RelativeLayout background;
    public static final String MY_PREFS_NAME = "MyPrefs";
    Editor editor;
    SharedPreferences sharedpreference;

    @Override
    protected void onCreate(Bundle savedInstanceState) {
        // TODO Auto-generated method stub
        super.onCreate(savedInstanceState);

        setContentView(R.layout.preferences);

        background = (RelativeLayout) findViewById(R.id.p_rl);

        ArrayAdapter<String> adapter = new ArrayAdapter<String>(this,
                R.layout.lv_activity, pref_list);

        ListView listView = (ListView) findViewById(R.id.pref_list);
        listView.setAdapter(adapter);

        listView.setOnItemClickListener(new OnItemClickListener() {

            @Override
            public void onItemClick(AdapterView<?> parent, View view,
                    int position, long id) {
                if (position == 0) {

                    colorpicker();
                } else {
                    Intent intent = new Intent();
                    intent.setType("image/*");
                    intent.setAction(Intent.ACTION_GET_CONTENT);
                    startActivityForResult(
                            Intent.createChooser(intent, "Select Picture"), 1);
                }
            }
        });
    }

    public void colorpicker() {

        AmbilWarnaDialog dialog = new AmbilWarnaDialog(this, 0xff0000ff,
                new OnAmbilWarnaListener() {

                    @Override
                    public void onCancel(AmbilWarnaDialog dialog) {
                    }

                    @Override
                    public void onOk(AmbilWarnaDialog dialog, int color) {
                        SharedPreferences sharedpreference = getApplicationContext()
                                .getSharedPreferences(MY_PREFS_NAME, MODE_PRIVATE);
                        Editor editor = sharedpreference.edit();
                        editor.putInt("Color code", color);
                        editor.commit();
                        Preferences.this.findViewById(R.id.p_rl)
                                .setBackgroundColor(color);
                        Preferences.this.findViewById(R.id.pref_list)
                                .setBackgroundColor(color);

                    }

                });
        dialog.show();
    }

    public void run(View view) {
        SharedPreferences sharedpreference = getSharedPreferences(
                MY_PREFS_NAME, MODE_PRIVATE);
        sharedpreference.getInt("Color code", 0);

        editor.commit();

    }
}

但这不仅仅是工作！我的代码有什么问题？

Answer 1

像这样更改你的onItemClick监听器

SharedPreferences sharedPreferences = getApplicationContext().getSharedPreferences(MY_PREFS_NAME, MODE_PRIVATE);
int selectedColor = sharedpreference.getInt("color", 0);
listView.setItemChecked(selectedColor, true);

并将其添加到onCreate

Person

Answer 2

您需要在onCreate或onResume上获取您在sharedPreference上保存的数据。因此，一旦应用程序启动，您可以应用您保存的任何颜色。

Answer 3

  //add param in that function
  public void colorpicker(int color) { 

        AmbilWarnaDialog dialog = new AmbilWarnaDialog(this, color,
                new OnAmbilWarnaListener() { 
        //your code
        }
  }


  //call this function in that way:
  colorpicker(getSharedPreferences(MY_PREFS_NAME, MODE_PRIVATE).getInt("Color code", 0xff0000ff));

所以只需使用保存的数据。目前你不会这样做。

从ColorPicker Android保存颜色int？

3 个答案: