我想将某个Drawable
设置为设备的壁纸,但所有壁纸功能仅接受Bitmap
。我不能使用WallpaperManager
因为我是2.1之前。
此外,我的drawables是从网上下载的,不在R.drawable
。
答案 0 :(得分:1211)
这段代码有帮助。
Bitmap icon = BitmapFactory.decodeResource(context.getResources(),
R.drawable.icon_resource);
此处是下载图片的版本。
String name = c.getString(str_url);
URL url_value = new URL(name);
ImageView profile = (ImageView)v.findViewById(R.id.vdo_icon);
if (profile != null) {
Bitmap mIcon1 =
BitmapFactory.decodeStream(url_value.openConnection().getInputStream());
profile.setImageBitmap(mIcon1);
}
答案 1 :(得分:691)
public static Bitmap drawableToBitmap (Drawable drawable) {
Bitmap bitmap = null;
if (drawable instanceof BitmapDrawable) {
BitmapDrawable bitmapDrawable = (BitmapDrawable) drawable;
if(bitmapDrawable.getBitmap() != null) {
return bitmapDrawable.getBitmap();
}
}
if(drawable.getIntrinsicWidth() <= 0 || drawable.getIntrinsicHeight() <= 0) {
bitmap = Bitmap.createBitmap(1, 1, Bitmap.Config.ARGB_8888); // Single color bitmap will be created of 1x1 pixel
} else {
bitmap = Bitmap.createBitmap(drawable.getIntrinsicWidth(), drawable.getIntrinsicHeight(), Bitmap.Config.ARGB_8888);
}
Canvas canvas = new Canvas(bitmap);
drawable.setBounds(0, 0, canvas.getWidth(), canvas.getHeight());
drawable.draw(canvas);
return bitmap;
}
答案 2 :(得分:204)
这会将BitmapDrawable转换为位图。
Drawable d = ImagesArrayList.get(0);
Bitmap bitmap = ((BitmapDrawable)d).getBitmap();
答案 3 :(得分:134)
可以在Drawable
上绘制Canvas
,Canvas
可以支持Bitmap
:
(已更新以处理BitmapDrawable
的快速转换并确保创建的Bitmap
具有有效大小)
public static Bitmap drawableToBitmap (Drawable drawable) {
if (drawable instanceof BitmapDrawable) {
return ((BitmapDrawable)drawable).getBitmap();
}
int width = drawable.getIntrinsicWidth();
width = width > 0 ? width : 1;
int height = drawable.getIntrinsicHeight();
height = height > 0 ? height : 1;
Bitmap bitmap = Bitmap.createBitmap(width, height, Bitmap.Config.ARGB_8888);
Canvas canvas = new Canvas(bitmap);
drawable.setBounds(0, 0, canvas.getWidth(), canvas.getHeight());
drawable.draw(canvas);
return bitmap;
}
答案 4 :(得分:32)
方法1 :您可以直接转换为这样的位图
Bitmap myLogo = BitmapFactory.decodeResource(context.getResources(), R.drawable.my_drawable);
方法2 :您甚至可以将资源转换为drawable,从中可以获得这样的位图
Bitmap myLogo = ((BitmapDrawable)getResources().getDrawable(R.drawable.logo)).getBitmap();
API&gt; 22 getDrawable
方法已移至ResourcesCompat
类,因此您可以执行此类操作
Bitmap myLogo = ((BitmapDrawable) ResourcesCompat.getDrawable(context.getResources(), R.drawable.logo, null)).getBitmap();
答案 5 :(得分:31)
非常简单
Bitmap tempBMP = BitmapFactory.decodeResource(getResources(),R.drawable.image);
答案 6 :(得分:14)
因此,在查看(和使用)其他答案后,似乎他们都严重处理ColorDrawable
和PaintDrawable
。 (特别是在棒棒糖上)似乎Shader
被调整了,因此没有正确处理明确的颜色块。
我现在使用以下代码:
public static Bitmap drawableToBitmap(Drawable drawable) {
if (drawable instanceof BitmapDrawable) {
return ((BitmapDrawable) drawable).getBitmap();
}
// We ask for the bounds if they have been set as they would be most
// correct, then we check we are > 0
final int width = !drawable.getBounds().isEmpty() ?
drawable.getBounds().width() : drawable.getIntrinsicWidth();
final int height = !drawable.getBounds().isEmpty() ?
drawable.getBounds().height() : drawable.getIntrinsicHeight();
// Now we check we are > 0
final Bitmap bitmap = Bitmap.createBitmap(width <= 0 ? 1 : width, height <= 0 ? 1 : height,
Bitmap.Config.ARGB_8888);
Canvas canvas = new Canvas(bitmap);
drawable.setBounds(0, 0, canvas.getWidth(), canvas.getHeight());
drawable.draw(canvas);
return bitmap;
}
与其他人不同,如果您在要求将其转换为位图之前在setBounds
上调用Drawable
,则会以正确的尺寸绘制位图!
答案 7 :(得分:13)
也许这会对某人有所帮助......
从PictureDrawable到Bitmap,使用:
private Bitmap pictureDrawableToBitmap(PictureDrawable pictureDrawable){
Bitmap bmp = Bitmap.createBitmap(pictureDrawable.getIntrinsicWidth(), pictureDrawable.getIntrinsicHeight(), Config.ARGB_8888);
Canvas canvas = new Canvas(bmp);
canvas.drawPicture(pictureDrawable.getPicture());
return bmp;
}
......如此实施:
Bitmap bmp = pictureDrawableToBitmap((PictureDrawable) drawable);
答案 8 :(得分:12)
最新的androidx核心库(androidx.core:core-ktx:1.2.0)现在具有extension function: Drawable.toBitmap(...)
,可将Drawable转换为位图。
答案 9 :(得分:10)
这是更好的解决方案
public static Bitmap drawableToBitmap (Drawable drawable) {
if (drawable instanceof BitmapDrawable) {
return ((BitmapDrawable)drawable).getBitmap();
}
Bitmap bitmap = Bitmap.createBitmap(drawable.getIntrinsicWidth(), drawable.getIntrinsicHeight(), Config.ARGB_8888);
Canvas canvas = new Canvas(bitmap);
drawable.setBounds(0, 0, canvas.getWidth(), canvas.getHeight());
drawable.draw(canvas);
return bitmap;
}
public static InputStream bitmapToInputStream(Bitmap bitmap) {
int size = bitmap.getHeight() * bitmap.getRowBytes();
ByteBuffer buffer = ByteBuffer.allocate(size);
bitmap.copyPixelsToBuffer(buffer);
return new ByteArrayInputStream(buffer.array());
}
答案 10 :(得分:8)
Android提供了一种非直接的解决方案:BitmapDrawable
。要获取位图,我们必须向a R.drawable.flower_pic
提供资源ID BitmapDrawable
,然后将其转换为Bitmap
。
Bitmap bm = ((BitmapDrawable) getResources().getDrawable(R.drawable.flower_pic)).getBitmap();
答案 11 :(得分:8)
以下是@ Chris.Jenkins提供的答案的好Kotlin版本:https://stackoverflow.com/a/27543712/1016462
fun Drawable.toBitmap(): Bitmap {
if (this is BitmapDrawable) {
return bitmap
}
val width = if (bounds.isEmpty) intrinsicWidth else bounds.width()
val height = if (bounds.isEmpty) intrinsicHeight else bounds.height()
return Bitmap.createBitmap(width.nonZero(), height.nonZero(), Bitmap.Config.ARGB_8888).also {
val canvas = Canvas(it)
setBounds(0, 0, canvas.width, canvas.height)
draw(canvas)
}
}
private fun Int.nonZero() = if (this <= 0) 1 else this
答案 12 :(得分:5)
使用此代码。它将帮助您实现目标。
Bitmap bmp=BitmapFactory.decodeResource(getResources(), R.drawable.profileimage);
if (bmp!=null) {
Bitmap bitmap_round=getRoundedShape(bmp);
if (bitmap_round!=null) {
profileimage.setImageBitmap(bitmap_round);
}
}
public Bitmap getRoundedShape(Bitmap scaleBitmapImage) {
int targetWidth = 100;
int targetHeight = 100;
Bitmap targetBitmap = Bitmap.createBitmap(targetWidth,
targetHeight,Bitmap.Config.ARGB_8888);
Canvas canvas = new Canvas(targetBitmap);
Path path = new Path();
path.addCircle(((float) targetWidth - 1) / 2,
((float) targetHeight - 1) / 2,
(Math.min(((float) targetWidth),
((float) targetHeight)) / 2),
Path.Direction.CCW);
canvas.clipPath(path);
Bitmap sourceBitmap = scaleBitmapImage;
canvas.drawBitmap(sourceBitmap,
new Rect(0, 0, sourceBitmap.getWidth(),
sourceBitmap.getHeight()),
new Rect(0, 0, targetWidth, targetHeight), new Paint(Paint.FILTER_BITMAP_FLAG));
return targetBitmap;
}
答案 13 :(得分:5)
1)可绘制到位图:
Bitmap mIcon = BitmapFactory.decodeResource(context.getResources(),R.drawable.icon);
// mImageView.setImageBitmap(mIcon);
2)位图到Drawable:
Drawable mDrawable = new BitmapDrawable(getResources(), bitmap);
// mImageView.setDrawable(mDrawable);
答案 14 :(得分:4)
位图位图= BitmapFactory.decodeResource(context.getResources(), R.drawable.icon);
例如,如果您的drawable是图层列表drawable却给出了空响应,那么这将不会每次都起作用,因此,作为替代方案,您需要将drawable绘制到画布中,然后另存为位图,请参考以下代码。
public void drawableToBitMap(Context context, int drawable, int widthPixels, int heightPixels) {
try {
File file = new File(Environment.getExternalStoragePublicDirectory(Environment.DIRECTORY_DOWNLOADS) + "/", "drawable.png");
FileOutputStream fOut = new FileOutputStream(file);
Drawable drw = ResourcesCompat.getDrawable(context.getResources(), drawable, null);
if (drw != null) {
convertToBitmap(drw, widthPixels, heightPixels).compress(Bitmap.CompressFormat.PNG, 100, fOut);
}
fOut.flush();
fOut.close();
} catch (Exception e) {
e.printStackTrace();
}
}
private Bitmap convertToBitmap(Drawable drawable, int widthPixels, int heightPixels) {
Bitmap bitmap = Bitmap.createBitmap(widthPixels, heightPixels, Bitmap.Config.ARGB_8888);
Canvas canvas = new Canvas(bitmap);
drawable.setBounds(0, 0, widthPixels, heightPixels);
drawable.draw(canvas);
return bitmap;
}
以上代码可将您保存为drawable.png的下载目录
答案 15 :(得分:1)
// get image path from gallery
protected void onActivityResult(int requestCode, int resultcode, Intent intent) {
super.onActivityResult(requestCode, resultcode, intent);
if (requestCode == 1) {
if (intent != null && resultcode == RESULT_OK) {
Uri selectedImage = intent.getData();
String[] filePathColumn = {MediaStore.Images.Media.DATA};
Cursor cursor = getContentResolver().query(selectedImage, filePathColumn, null, null, null);
cursor.moveToFirst();
int columnIndex = cursor.getColumnIndex(filePathColumn[0]);
filePath = cursor.getString(columnIndex);
//display image using BitmapFactory
cursor.close(); bmp = BitmapFactory.decodeFile(filepath);
iv.setBackgroundResource(0);
iv.setImageBitmap(bmp);
}
}
}
答案 16 :(得分:1)
ImageWorker库可以将位图转换为drawable或base64,反之亦然。
Sub Test()
Dim arr, rng As Range, c As Range, n As Long
Set rng = Range("P2:P" & Cells(Rows.Count, "P").End(xlUp).Row).SpecialCells(xlCellTypeVisible)
ReDim a(1 To rng.Cells.Count)
For Each c In rng
n = n + 1: a(n) = c.Value
Next c
arr = Join(a, ",")
End Sub
实施
在项目级别Gradle中
val bitmap: Bitmap? = ImageWorker.convert().drawableToBitmap(sourceDrawable)
在应用程序级别绑定中
allprojects {
repositories {
...
maven { url 'https://jitpack.io' }
}
}
您还可以从外部存储和检索位图/可绘制对象/ base64图像。
在这里检查。 https://github.com/1AboveAll/ImageWorker/edit/master/README.md
答案 17 :(得分:0)
android-ktx具有Drawable.toBitmap
方法:https://android.github.io/android-ktx/core-ktx/androidx.graphics.drawable/android.graphics.drawable.-drawable/to-bitmap.html
来自Kotlin
val bitmap = myDrawable.toBitmap()
答案 18 :(得分:0)
BitmapFactory.decodeResource()
自动缩放位图,因此您的位图可能变得模糊。为防止缩放,请执行以下操作:
BitmapFactory.Options options = new BitmapFactory.Options();
options.inScaled = false;
Bitmap source = BitmapFactory.decodeResource(context.getResources(),
R.drawable.resource_name, options);
或
InputStream is = context.getResources().openRawResource(R.drawable.resource_name)
bitmap = BitmapFactory.decodeStream(is);
答案 19 :(得分:0)
如果您正在使用kotlin,请使用以下代码。会起作用的
//用于使用图像路径
const [textareaValue, setTextareaValues] = React.useState([])
const handleSelectedItem = item => {
setTextareaValues([...textareaValue, item]))
}