I have been having some trouble获取Django SessionWizardView将数据提交到我的数据库,我试图找出问题。
注意到
除了元素外,表单还必须指定两个内容:
- 其中:应返回与用户输入相对应的数据的URL
- 如何:
返回数据的HTTP方法
和
发送回Django网站的表单数据由视图处理, 通常与发布表格的观点相同。这允许我们 重用一些相同的逻辑。
目前我正在使用<form action="/surveyone/" method="post">
,我认为这是正确的。
问题是我的观点被称为class SurveyWizardOne(SessionWizardView):
,但如果我尝试在form action
中使用此视图,则在调查的第一页上单击“下一步”后,我会收到错误。
问题:根据以下内容action="/surveyone/"
是否正确?
谢谢
urls.py
url(r'^surveyone/$', SurveyWizardOne.as_view([
SurveyFormIT1,
SurveyFormIT2,
Start,
SurveyFormA,
SurveyFormB,
SurveyFormC,
SurveyFormD,
SurveyFormE,
SurveyFormSpike1,
SurveyFormF1,
SurveyFormF2,
SurveyFormF3,
SurveyFormDV1,
SurveyFormF4,
SurveyFormF5,
SurveyFormF6,
SurveyFormSpike2,
SurveyFormDV2,
SurveyFormF7,
SurveyFormF8,
SurveyFormF9,
SurveyFormDV3,
SurveyFormDV4,
SurveyFormDV5,
SurveyFormG,
SurveyFormH,
SurveyFormI
])),
views.py
class SurveyWizardOne(SessionWizardView):
def get_context_data(self, form, **kwargs):
context = super(SurveyWizardOne, self).get_context_data(form, **kwargs)
step = int(self.steps.current)
....
....
return context
def done(self, form_list, **kwargs):
return render(self.request, 'Return_to_AMT.html', {
'form_data': [form.cleaned_data for form in form_list],
})
wizard_form.html
{% extends "base.html" %}
{% load i18n %}
{% block head %}
{{ wizard.form.media }}
{% endblock %}
{% block content %}
<div class="main_content">
<p>Page: {{ wizard.steps.step1 }} of {{ wizard.steps.count }}</p>
<form action="/surveyone/" method="post">{% csrf_token %}
<table>
{{ wizard.management_form }}
{% if wizard.form.forms %}
{{ wizard.form.management_form }}
{% for form in wizard.form.forms %}
{{ form }}
{% endfor %}
{% else %}
{{ wizard.form }}
{% endif %}
</table>
答案 0 :(得分:1)
由于您的表单提交到同一网址,因此您只需使用action=""
即可。如果您愿意,可以使用action="/surveyone/"
如果您不想在模板中对网址进行硬编码,则需要name your url patterns:
url(r'^surveyone/$', SurveyWizardOne.as_view([
SurveyFormIT1,
SurveyFormH,
...
]), name="survey_one"),
然后,您可以在模板中使用url标记:
action="{% url 'survey_one' %}"