Question

所以，我一直在编写一些PHP，我从数据库中获取一些数据进行输出。我正常使用函数，但由于某些原因，函数中被拒绝的变量显然是未声明的？

这是我的代码：

function fetchUserData($localUser_id) {

    include_once("../../../conConfig/connectToDatabase.php");

    $dataQuery = mysqli_query($dbConnect, "SELECT users.emailAddress, userInfo.fullName, userInfo.initials, userInfo.maxWorkspaces FROM users INNER JOIN userInfo ON userInfo.ID = users.ID WHERE users.ID = ".$localUser_id."");
    $queryResult = mysqli_fetch_array($dataQuery, MYSQLI_ASSOC);

    $db_dash_userName   = $queryResult["fullName"];
    $db_dash_userEmail  = $queryResult["emailAddress"];
    $db_dash_userIcon   = "initials";
    $db_dash_userMaxW   = $queryResult["maxWorkspaces"];
    $db_dash_userInit   = $queryResult["initials"];

    echo $db_dash_userName.$db_dash_userEmail.$db_dash_userIcon.$db_dash_userMaxW.$db_dash_userInit."<br><br><br>";

}

//$localUser_id = $_SESSION["user_id"];
$localUser_id = 1;
fetchUserData($localUser_id);

echo $db_dash_userName.$db_dash_userEmail.$db_dash_userIcon.$db_dash_userMaxW.$db_dash_userInit;

它可能有什么问题？它返回一个值，由函数内部的回声输出，但它们不会被最终的回声输出。

是的，我已经尝试过返回variable.variable ......＆＃39;，但仍然无法解决问题。

提前致谢。

Answer 1

您需要从函数返回值。 echoing不返回值。您还需要将返回的值分配给变量并使用它来显示输出。

function fetchUserData($localUser_id) {

        include_once("../../../conConfig/connectToDatabase.php");

        $dataQuery = mysqli_query($dbConnect, "SELECT users.emailAddress, userInfo.fullName, userInfo.initials, userInfo.maxWorkspaces FROM users INNER JOIN userInfo ON userInfo.ID = users.ID WHERE users.ID = ".$localUser_id."");
        $queryResult = mysqli_fetch_array($dataQuery, MYSQLI_ASSOC);

        $db_dash_userName   = $queryResult["fullName"];
        $db_dash_userEmail  = $queryResult["emailAddress"];
        $db_dash_userIcon   = "initials";
        $db_dash_userMaxW   = $queryResult["maxWorkspaces"];
        $db_dash_userInit   = $queryResult["initials"];

        return $db_dash_userName.$db_dash_userEmail.$db_dash_userIcon.$db_dash_userMaxW.$db_dash_userInit."<br><br><br>";

    }

    //$localUser_id = $_SESSION["user_id"];
    $localUser_id = 1;
    $output = fetchUserData($localUser_id);

    echo $output;

PHP变量未定义，但我将它们设置为函数

1 个答案: