Question

我有一系列Dropdownlist控件。当我将所选值设置为1时，它会为所有值设置它们。我做错了什么？

Dropdownlist[] _ddl = new Dropdownlist[7];

for(int i=0;i<=6;i++)
{
    _dll[i] = new Dropdownlist();
    _dll[i].ID = "dropdown" + i;
    _ddl[i].AutoPostBack = true;
    _ddl[i].Items.AddRange(GradeLevels);
    if (Grade == "A")
    _ddl[i].Items.FindByValue("A").Selected = true;

}

Answer 1

我建议你使用

    String Grade = "A";
    string[] GradeLevels = new string[] { "A", "B", "C" };
    DropDownList _ddl = new DropDownList();
    _ddl.AutoPostBack=true;
    for (int i = 0; i < GradeLevels.Length; i++)
    {
        _ddl.Items.Add(new ListItem(GradeLevels[i], GradeLevels[i]));
    }
        _ddl.Items.FindByValue(Grade).Selected = true;
    PlaceHolder1.Controls.Add(_ddl);

Answer 2

试试这个：

    Dropdownlist[] _ddl = new Dropdownlist[6];

    for(int i = 0; i < 6; i++)
    {
        _dll[i] = new Dropdownlist();
        _dll[i].ID = "dropdown" + i;
        _ddl[i].AutoPostBack = true;
        _ddl[i].Items.AddRange(GradeLevels);       
    }

    // set the selected item in the first list
    if (Grade == "A")
        _ddl[0].Items.FindByValue("A").Selected = true;

Answer 3

您必须创建GradeLevels对象的克隆副本，并向每个Dropdownlist添加该对象的不同副本。

Answer 4

顺便说一句，我用它来解决这个问题。

http://leekelleher.com/2008/11/24/populating-multiple-dropdownlist-controls-with-generic-listitem-array/

下拉列表控件数组具有相同的值

4 个答案: