Question

我正在开发一些基于目录的项目，其中包含无限制的嵌套（实际上，最高级别为3，我猜，但它必须是动态的。）

让我说明做了什么：

OrganizationCategory模型：

public function relations()
{
    return array(
        'organizations' => array(self::HAS_MANY, 'Organization', 'organization_category_id'),
        'parent' => array(self::BELONGS_TO, 'OrganizationCategory', 'category_parent_id'),
        'children' => array(self::HAS_MANY, 'OrganizationCategory', 'category_parent_id'),
    );
}

public static function getParentCategories()
{
    if (is_null(self::$categories))
    {
        self::$categories = array();
        $criteria = new CDbCriteria();
        $criteria->order = 't.category_title';
        $criteria->condition = "t.category_parent_id IS NULL";
        $arr = self::model()->with('children')->findAll($criteria);
        foreach ($arr as $item)
            self::$categories[$item->primaryKey] = $item;
    }

    return self::$categories;
}

public static function createTree($children, $counter)
{
    $tree = '';

    if(count($children)){

        $tree .= CHtml::tag('ul', array('class'=>'menu_open_'.$counter));

        foreach($children as $child):

            $childrenSub = self::createTree($child->children, $counter+1);

            $tree .= CHtml::tag('li',  (empty($childrenSub) ? array('class'=>'no_child_li') : array()));

            $organizations = Organization::model()->findByAttributes(array('organization_category_id'=>$child->category_id));

            $tree .= CHtml::link($child->category_title, array('organizationCategory/view', 'slug'=>$child->category_slug));

            $tree .= $childrenSub;
            $tree .=CHtml::closeTag('li');

        endforeach;

        $tree .= CHtml::closeTag('ul');

    }

    return $tree;
}

CategoryController：

public function actionView($slug = '')
{
    $model = $this->loadModelSlug($slug);

    $organizationsList = Organization::getOrganizations($model->category_id);

    $this->pageTitle=$model->category_title;
    Yii::app()->clientScript->registerMetaTag($model->meta_description, 'description');
    Yii::app()->clientScript->registerMetaTag($model->meta_keywords, 'keywords');

    $this->render('view',array(
        'model'=>$model,
        'organizationsList'=>$organizationsList,
    ));
}

组织模型getOrganizations（）：

public static function getOrganizations($category_id) {

    $criteria = new CDbCriteria;
    $criteria->condition = 'organization_category_id = :cat_id';
    $criteria->params = array(':cat_id'=>$category_id);
    $result = self::model()->findAll($criteria);

    return $result;
}

分类view.php

<?php if(!empty($model->children)) {
echo OrganizationCategory::model()->createTree($model->children, 1); 
} ?>

<?php $i=1; foreach($model->organizations as $organization): ?>
    blah blah blah
<?php $i++; endforeach; ?>

您可以猜到，现在我只能获得那些仅与当前显示的类别相关联的产品。

我的目标是从类别及其所有子类别中获取产品 - ＆gt;子类别 - >子类别。

我试图在几乎所有地方找到解决方案，但仍然无法在我的项目中实现这个简单的任务。

感谢您提供的任何帮助，谢谢

Answer 1

对于其他可能对此问题感兴趣的人，我已经解决了这个问题：

在类别控制器视图操作中，我调用：

$model = $this->loadModelSlug($slug);
$organizationsList = Organization::getOrganizationsFromSubcategories($model);

在组织模型中：

public static function getOrganizationsFromSubcategories($category) {

    $childCategoriesIds = OrganizationCategory::getChildCategoriesIds($category);

    $criteria = new CDbCriteria();
    $criteria->addInCondition('organization_category_id', $childCategoriesIds);
    $result = self::model()->findAll($criteria);

    return $result;
}

最后，在OrganizationCategory：

public static function getChildCategoriesIds($category)
{
    $arr = array($category->primaryKey);

    if (!empty($category->children))
        foreach ($category->children as $child_category) $arr = array_merge($arr, self::getChildCategoriesIds($child_category));

    return $arr;
}

Yii 1.从类别及其子类别中获取产品[无限嵌套]

1 个答案: