如何在asp.net mvc4中创建具有泛型参数的通用基本控制器

时间:2015-05-20 12:39:53

标签: c# asp.net-mvc-4

我遇到如何制作通用控制器的问题。我有Model,id属性可以是string或int的类型。当我想编辑一个id为int的模型时,我找不到导致错误的动作,因为我实现了 公共抽象ActionResult Edit(字符串id)的覆盖方法。

存在一种传递我的路线可以承受的通用参数(字符串或整数)的方法吗?

public abstract class BaseController<T> : Controller
{
    //protected UnitOfWork unitOfWork = new           UnitOfWork(System.Web.HttpContext.Current.User.Identity.Name);        
    protected UnitOfWork unitOfWork = new UnitOfWork("");
    public abstract ActionResult List();
    public abstract ActionResult Index();
    public abstract ActionResult Details(string id);, 
    public abstract ActionResult CreateByModal();
    public abstract ActionResult Create();
    [HttpPost]
    [ValidateAntiForgeryToken]
    public abstract ActionResult Create(T entity);
    public abstract ActionResult Edit(string id);
    [HttpPost]
    [ValidateAntiForgeryToken]
    public abstract ActionResult Edit(T entity);       
    public abstract ActionResult Delete(string id);

    protected override void Dispose(bool disposing)
    {
        //db.Dispose();
        base.Dispose(disposing);
    }
}

 public class ModeloController : BaseController<Modelo>
{
    public override ActionResult Edit(string id)
    {
       //Here i have a int Id im my Model  and the error in my route
        Modelo modelo = unitOfWork.ModeloRepository.Find(id);
        if (modelo == null)
        {
            return HttpNotFound();
        }
        return PartialView("_Edit", modelo);
    }
}


public class GeneroController : BaseController<Genero>
{
    //Here i have a string Id im my Model 
    public override ActionResult Edit(string id)
    {
        Genero genero = unitOfWork.GeneroRepository.Find(id);
        if (genero == null)
        {
            return HttpNotFound();
        }
        return PartialView("_Edit", genero);
    }

}

2 个答案:

答案 0 :(得分:2)

一种选择是重载具有id作为参数的每个方法:

public abstract ActionResult Details(string id);
public abstract ActionResult Details(int id); 

或者为id的类型添加第二个通用参数:

public abstract class BaseController<T, U> : Controller
{
    public abstract ActionResult Details(U id);
    public abstract ActionResult Edit(U id);

无论哪种方式,您都要对来电者承担更多责任,以确保使用正确的类型。

答案 1 :(得分:1)

您可以添加其他泛型类型参数来指示给定类的键类型。

public abstract class AbstractController<TEntity, TId> : Controller
{
    // irrelevant stuff omitted
    public ActionResult Edit(TEntity id);
}