Question

以下代码是我尝试查找频率表中的最小两个值。我不想使用任何排序算法。一旦我检测到数组中的两个最小值。我保存他们的索引并执行添加。到目前为止我已经这样做了。有人可以帮我这个吗？那现在我该做什么。感谢

freq   dd 512 dup(0)
min    dw ? 

smallval proc
push bx
sub bx,bx

cal:
mov ax,freq[bx]  ;moving the address of frequence to source index
cmp ax,0        ;comparing the frequency array one by one
jmp incr        ;increased the address of frequency by two since its a byte
call check
mov freq[bx],0  ;replace that min value with zero
mov ind,bx 

cal1:
add bx,2        ;now trying to find the next smallest value in the array
mov ax,freq[bx]
cmp ax,0
jmp cal1
call check
mov freq[bx],0
add ax,min      ;addition of two minimum values

incr:
add bx,2
jmp cal

endval:
smallval endp

;=======================================================================================
;checking for the smallest value in the array

check proc
mov ax,freq[bx]          ;assigning lowest value in the frequency array in min 
variable
mov min,ax

l1:                       ;loop that checks each value of array with min 
variable
add bx,2                  ;and see if something is smaller then that will be a 
new min
mov ax,freq[bx]
cmp min,ax
jge assign
cmp bx,1024
jmp end
jmp l1

assign:                   ;upon next smallest value min variable will be 
replaced by that
mov ax,freq[bx]           ;smallest value
mov min,ax
jmp l1

end:
ret
check endp

Answer 1

这里有一个无限循环：

cal1:
add bx,2
mov ax,freq[bx]
cmp ax,0
jmp cal1

这里有一些可疑的流量控制：

cmp bx,1024
jmp end
jmp l1

我想在一个数组中找到最小的两个值并进行任何排序

1 个答案: