我想测试设备是否已植根?为此,我使用以下代码,此代码在设备上正常工作,但在模拟器上它显示它是root。
public class RootUtil {
public static boolean isDeviceRooted() {
return (checkRootMethod1()||checkRootMethod2() || checkRootMethod3()|| checkRootMethod4()||checkRootMethod5()) ;
}
private static boolean checkRootMethod1() {
System.out.println ("Inside checkRootMethod1");
String buildTags = android.os.Build.TAGS;
if (buildTags != null && buildTags.contains("test-keys")) {
System.out.println ("Inside if of 1");
return true;
}
return false;
}
private static boolean checkRootMethod2() {
System.out.println("checkRootMethod2"+new File("/system/app/Superuser.apk").exists());
return new File("/system/app/Superuser.apk").exists();
}
private static boolean checkRootMethod3() {
String[] paths = { "/sbin/su", "/system/bin/su", "/system/xbin/su", "/data/local/xbin/su", "/data/local/bin/su", "/system/sd/xbin/su",
"/system/bin/failsafe/su", "/data/local/su" };
for (String path : paths) {
System.out.println("checkRootMethod3"+new File(path).exists());
if (new File(path).exists()) return true;
}
return false;
}
private static boolean checkRootMethod4() {
Process process = null;
try {
process = Runtime.getRuntime().exec(new String[] { "/system/xbin/which", "su" });
BufferedReader in = new BufferedReader(new InputStreamReader(process.getInputStream()));
System.out.println("checkRootMethod4"+in.readLine() != null);
if (in.readLine() != null) return true;
return false;
} catch (Throwable t) {
return false;
} finally {
if (process != null) process.destroy();
}
}
private static boolean checkRootMethod5() {
return canExecuteCommand("/system/xbin/which su")
|| canExecuteCommand("/system/bin/which su")
|| canExecuteCommand("which su");
}
private static boolean canExecuteCommand(String command) {
boolean executedSuccesfully;
try {
Runtime.getRuntime().exec(command);
executedSuccesfully = true;
} catch (Exception e) {
executedSuccesfully = false;
}
return executedSuccesfully;
}
}
是否还有其他条件需要检查设备是否已植根?因为我在网上看到有各种方法使用上面的代码将无法正常工作。任何建议将不胜感激。提前谢谢。
答案 0 :(得分:0)
查看库RootTools 4.2它非常适合检查root和其他root用户。