使用正则表达式从字符串中检索数字

时间:2015-05-19 19:25:50

标签: ruby regex

我有一个字符串,它以下面的格式返回持续时间。

"152M0S" or "1H22M32S"

我需要从中提取小时,分钟和秒数作为数字。

我尝试了下面的正则表达式

video_duration.scan(/(\d+)?.(\d+)M(\d+)S/)

但它没有按预期返回。任何人都知道我在哪里错了。

4 个答案:

答案 0 :(得分:2)

"1H22M0S".scan(/\d+/)
#=> ["1", "22", "0']

答案 1 :(得分:1)

您可以使用此表达式:/((?<h>\d+)H)?(?<m>\d+)M(?<s>\d+)S/

"1H22M32S".match(/((?<h>\d+)H)?(?<m>\d+)M(?<s>\d+)S/)
#=> #<MatchData "1H22M32S" h:"1" m:"22" s:"32">

"152M0S".match(/((?<h>\d+)H)?(?<m>\d+)M(?<s>\d+)S/)
#=> #<MatchData "152M0S" h:nil m:"152" s:"0">

组后的问号使其成为可选项。要访问数据:$~[:h]

答案 2 :(得分:1)

如果您想提取数字,可以这样做:

"1H22M32S".match(/(?<hour>(\d+))H(?<min>(\d+))M(?<sec>(\d+))S/i).captures
# => ["1", "22", "32"]
"1H22M32S".match(/(?<hour>(\d+))H(?<min>(\d+))M(?<sec>(\d+))S/i)['min']
# => "22"
"1H22M32S".match(/(?<hour>(\d+))H(?<min>(\d+))M(?<sec>(\d+))S/i)['hour']
# => "1"

答案 3 :(得分:1)

我,我hashify

def hashify(str)
  str.gsub(/\d+[HMS]/).with_object({}) { |s,h| h[s[-1]] = s.to_i }
end

hashify "152M0S"    #=> {"M"=>152, "S"=>0} 
hashify "1H22M32S"  #=> {"H"=>1, "M"=>22, "S"=>32} 
hashify "32S22M11H" #=> {"S"=>32, "M"=>22, "H"=>11} 
hashify "1S"        #=> {"S"=>1}