Question

我目前正致力于使一个应用与AppleWatch兼容，

为此，我正在调用一个WebService，问题是我在Block中收到WebService响应，并且 reply（）块没有被调用，显示错误。

错误，

The UIApplicationDelegate in the iPhone App never called reply() in -[UIApplicationDelegate application:handleWatchKitExtensionRequest:reply:]

我的Appdelegate，

func application(application: UIApplication, handleWatchKitExtensionRequest userInfo: [NSObject : AnyObject]?, reply: (([NSObject : AnyObject]!) -> Void)!) {

    getInfo(userInfo, reply: reply)

}

func getInfo(userInfo: [NSObject : AnyObject]!, reply: (([NSObject : AnyObject]!) ->Void)!){

    let dicParam:NSDictionary = [:]

    let wsfr:WSFrameWork = WSFrameWork(URLAndParams:WS_GET_DATA, dicParams: dicParam as [NSObject : AnyObject])

    wsfr.isLogging = false

    wsfr.onError = { (error : NSError!) -> Void in
        reply(nil)
    }

    wsfr.onSuccess = { (dicResponse : Dictionary!) -> Void in

        if dicResponse["data"] != nil{

            let returnData = ["Returned NSData":dicResponse]
            reply(returnData)

        }

    }
}

WSFrameWork是我们的WebService框架。

Answer 1

问题是方法handleWatchKitExtensionRequest在操作系统杀死之前没有完成。因此：

明确创建后台任务。
如果您想要异步获取数据，请确保在后台提取完成之前不会留下方法handleWatchKitExtensionRequest。

这是一个code example，展示了如何实现上述功能。

Answer 2

所以最后我通过执行Sync WS请求得到了答案，

func application(application: UIApplication, handleWatchKitExtensionRequest userInfo: [NSObject : AnyObject]?, reply: (([NSObject : AnyObject]!) -> Void)!) {

    getCurrentDataInfo(userInfo, reply: reply)

}

func getCurrentDataInfo(userInfo: [NSObject : AnyObject]!, reply: (([NSObject : AnyObject]!) ->Void)!){

    var data = parseJSON(getJSON("https://My_JSON_URL"))

    println(data)

    reply(["myData":data])

}

func getJSON(urlToRequest: String) -> NSData{
    return NSData(contentsOfURL: NSURL(string: urlToRequest)!)!
}

func parseJSON(inputData: NSData) -> NSDictionary{
    var error: NSError?
    var boardsDictionary: NSDictionary = NSJSONSerialization.JSONObjectWithData(inputData, options: NSJSONReadingOptions.MutableContainers, error: &error) as! NSDictionary

    return boardsDictionary
}

获取从Block到WatchKit App的WebService响应

2 个答案: