Question

我必须在table1中为table2中的每一行插入一个新行。问题是table2中的select返回的字段多于insert所需的字段，但在select的where子句中很有用。

此查询根据用户（商店）范围（在表商店中定义）向用户显示周围的所有商店

SELECT destination.poi_id,
  6371 * 
     2 * 
     ASIN(
       SQRT(
         POWER(SIN((use_lat - poi_lat) * PI()/180 / 2), 2) +
         COS(use_lat * pi()/180) * 
         COS(poi_lat * pi()/180) *
         POWER(SIN((use_lon - poi_lon) * PI()/180 / 2), 2)
       )
     ) AS distance,
  destination.poi_range AS range
FROM stores destination, users origin
WHERE origin.use_id=userid
  AND destination.poi_lon BETWEEN lon1 AND lon2
  AND destination.poi_lat BETWEEN lat1 AND lat2
  HAVING distance <= range
ORDER BY distance;

现在我必须将这些结果放在具有这种结构的表中

user_id  INTEGER
poi_id   INTEGER
ins_date TIMESTAMP (CURRENT TIMESTAMP)

我不知道该怎么做，你能帮助我吗？

INSERT INTO table (user_id, poi_id)
SELECT ... ? (too many fields in select)

Answer 1

在行之间读取一点但基本上只包括插入IE中需要的列：

INSERT INTO table (user_id, poi_id)
SELECT use_id,poi_id,NOW() FROM
    (SELECT origin.use_id,destination.poi_id,6371 * 
     2 * 
     ASIN(
       SQRT(
         POWER(SIN((use_lat - poi_lat) * PI()/180 / 2), 2) +
         COS(use_lat * pi()/180) * 
         COS(poi_lat * pi()/180) *
         POWER(SIN((use_lon - poi_lon) * PI()/180 / 2), 2)
       )
     ) as distance
    FROM stores destination, users origin
    WHERE origin.use_id=userid
      AND destination.poi_lon BETWEEN lon1 AND lon2
      AND destination.poi_lat BETWEEN lat1 AND lat2
      HAVING distance <= range) sub1
ORDER BY distance;

Answer 2

您只需添加select select_id并删除距离和范围，因为您的表中没有，实际上您必须添加ins_date，因为您没有在Insert中定义 VALUE 语句。所以你的选择应该是这样的

INSERT INTO table values (user_id, poi_id) 
   Select user_id, poi_id from FROM stores destination, users origin
WHERE origin.use_id=userid
  AND destination.poi_lon BETWEEN lon1 AND lon2
  AND destination.poi_lat BETWEEN lat1 AND lat2
  HAVING distance <= range
ORDER BY distance;

如果您需要在表格中添加日期，请在括号内包含此字段，也可在

MYSQL插入选择过滤字段

2 个答案: