Question

这种类型的数组的正确名称是什么？

有3个主要部分和4个子部分由“issuedTime”“text”“url”和“validToTime”组成，你如何开始将其转换为对象？如果只有1个主要部分，那么使用3个主要部分会相当简单，并且每个主要部分没有任何标识让我摸不着头脑从哪里开始。

任何建议都表示赞赏。

[{
"issuedTime":"7:13pm Sunday 13 June 2010",
"text":"\nAmended 7:10pm.\n\nText text and more text\n",
"url":"\/folder\/fc\/name.png",
"validToTime":"12:00am Monday 14 June 2010"
},{
"issuedTime":"8:33pm Sunday 13 June 2010",
"text":"\nText and more text.\n",
"url":"\/folder\/fc\/name.png",
"validToTime":"12:00pm Monday 14 June 2010"
},{
"issuedTime":"10:40am Sunday 13 June 2010",
"text":"\nAnd even more text.",
"url":"\/folder\/fc\/name.png",
"validToTime":"12:00am Tuesday 15 June 2010"
}
]

Answer 1

JSON (an acronym for JavaScript Object Notation) 是基于文字的轻量级广告开放式标准设计人类可读的数据交换。它是源自JavaScript 用于表示的编程语言简单的数据结构和关联数组，称为对象。尽管如此与JavaScript的关系，它是与语言无关，具有解析器适用于几乎所有人编程语言。

您可以使用 json_decode 函数轻松将其转换为php数组，以下是php网站的示例：

$json = '{"a":1,"b":2,"c":3,"d":4,"e":5}';
var_dump(json_decode($json, true));

<强>结果：

array(5) {
    ["a"] => int(1)
    ["b"] => int(2)
    ["c"] => int(3)
    ["d"] => int(4)
    ["e"] => int(5)
}

json_decode的第二个参数是它是否应该转换为关联数组。如果未指定第二个参数，则输出将如下：

object(stdClass)#1 (5) {
    ["a"] => int(1)
    ["b"] => int(2)
    ["c"] => int(3)
    ["d"] => int(4)
    ["e"] => int(5)
}

因此，您可以将其转换为数组并循环遍历它：

$json = '{"a":1,"b":2,"c":3,"d":4,"e":5}';
$array = json_decode($json, true);
print_r($array);

foreach($array as $key => $value)
{
   // manipulate the var $value
}

Answer 2

以下是解析json的方法

<?php
$json = '[{
    "issuedTime":"7:13pm Sunday 13 June 2010",
    "text":"\nAmended 7:10pm.\n\nText text and more text\n",
    "url":"\/folder\/fc\/name.png",
    "validToTime":"12:00am Monday 14 June 2010"
    },{
    "issuedTime":"8:33pm Sunday 13 June 2010",
    "text":"\nText and more text.\n",
    "url":"\/folder\/fc\/name.png",
    "validToTime":"12:00pm Monday 14 June 2010"
    },{
    "issuedTime":"10:40am Sunday 13 June 2010",
    "text":"\nAnd even more text.",
    "url":"\/folder\/fc\/name.png",
    "validToTime":"12:00am Tuesday 15 June 2010"
}]';
// Parse the json into a PHP array that holds multiple "stdClass Object"s
$obj = json_decode($json);  
// Iterate through each "stdClass Object" and show what it contains  
foreach($obj as $var => $value)
{
    echo "Number: $var <br/>";    
    echo "Issued: " . $obj[$var]->issuedTime . "<br/>";                    
    echo "Text: " . $obj[$var]->text . "<br/>";    
    echo "URL: " . $obj[$var]->url . "<br/>";    
    echo "Valid to: " . $obj[$var]->validToTime . "<br/>";       
    echo "<br/>";
}
?>

一旦你有了$ obj，就可以像上面的foreach循环那样访问它，或者访问，假设您要使用的第二个列表中的文本：

echo $obj[1]->text; // Second listing, since the first listing is $obj[0]

和HTML链接w文本相同：

echo '<a href="' . $obj[1]->url . '">' . $obj[1]->text . '</a>';

Answer 3

你试过json_decode()吗？它应该正确地解析为stdObject。

Answer 4

看看： http://www.lost-in-code.com/programming/php-code/php-array-to-object/

这是什么类型的对象以及如何使用它？

4 个答案: