Question

我对XSL很新。我正在尝试将XML转换为JSON

我正在使用的XSLT是`

<xsl:template match="/node()">
    <xsl:text>[</xsl:text>
    <xsl:apply-templates select="." mode="detect" />
    <xsl:text>]</xsl:text>
</xsl:template>

<xsl:template match="*" mode="detect">
    <xsl:choose>
        <xsl:when test="name(preceding-sibling::*[1]) = name(current()) and name(following-sibling::*[1]) != name(current())">
            <xsl:apply-templates select="." mode="obj-content" />
            <xsl:text>]</xsl:text>
            <xsl:if test="count(following-sibling::*[name() != name(current())]) &gt; 0">, </xsl:if>
        </xsl:when>
        <xsl:when test="name(preceding-sibling::*[1]) = name(current())">
                <xsl:apply-templates select="." mode="obj-content" />
                <xsl:if test="name(following-sibling::*) = name(current())">, </xsl:if>
        </xsl:when>
        <xsl:when test="following-sibling::*[1][name() = name(current())]">
            <xsl:text>"</xsl:text><xsl:value-of select="name()"/><xsl:text>" : [</xsl:text>
                <xsl:apply-templates select="." mode="obj-content" /><xsl:text>, </xsl:text> 
        </xsl:when>
        <xsl:when test="count(./child::*) > 0 or count(@*) > 0">
            <xsl:text>"</xsl:text><xsl:value-of select="name()"/>" : <xsl:apply-templates select="." mode="obj-content" />
            <xsl:if test="count(following-sibling::*) &gt; 0">, </xsl:if>
        </xsl:when>
        <xsl:when test="count(./child::*) = 0">
            <xsl:text>"</xsl:text><xsl:value-of select="name()"/>" : "<xsl:apply-templates select="."/><xsl:text>"</xsl:text>
            <xsl:if test="count(following-sibling::*) &gt; 0">, </xsl:if>
        </xsl:when>
    </xsl:choose>
</xsl:template>

<xsl:template match="*" mode="obj-content">


    <xsl:text>{</xsl:text>
        <xsl:apply-templates select="@*" mode="attr" />
        <xsl:if test="count(@*) &gt; 0 and (count(child::*) &gt; 0 or text())">, </xsl:if>
        <xsl:apply-templates select="./*" mode="detect" />
        <xsl:if test="count(child::*) = 0 and text() and not(@*)">
            <xsl:text>"</xsl:text><xsl:value-of select="name()"/>" : "<xsl:value-of select="text()"/><xsl:text>"</xsl:text>
        </xsl:if>
        <xsl:if test="count(child::*) = 0 and text() and @*">
            <xsl:text>"text" : "</xsl:text><xsl:value-of select="text()"/><xsl:text>"</xsl:text>
        </xsl:if>
    <xsl:text>}</xsl:text>
    <xsl:if test="position() &lt; last()">, </xsl:if>
</xsl:template>

<xsl:template match="@*" mode="attr">
    <xsl:text>"</xsl:text><xsl:value-of select="name()"/>" : "<xsl:value-of select="."/><xsl:text>"</xsl:text>
    <xsl:if test="position() &lt; last()">,</xsl:if>
</xsl:template>

<xsl:template match="node/@TEXT | text()" name="removeBreaks">
    <xsl:param name="pText" select="normalize-space(.)"/>
    <xsl:choose>
        <xsl:when test="not(contains($pText, '&#xA;'))"><xsl:copy-of select="$pText"/></xsl:when>
        <xsl:otherwise>
            <xsl:value-of select="concat(substring-before($pText, '&#xD;&#xA;'), ' ')"/>
            <xsl:call-template name="removeBreaks">
                <xsl:with-param name="pText" select="substring-after($pText, '&#xD;&#xA;')"/>
            </xsl:call-template>
        </xsl:otherwise>
    </xsl:choose>
</xsl:template>

`

我需要输出

  "InvoiceItems": [
  {
    "InvoiceLineNumber": "1",
    "DivisionCode": "300",
    "InvoicedQuantity": "1",
    "ProductInvoicedPrice": "26.50",
    "ProductName": "SAND DOLLARS S/S SHIRT",
    "ProductNumber": "CSHAH7BLKM",
    "InvoiceItemSizes": [
      {
        "InvoiceNumber": "101000003",
        "InvoiceLineNumber": "1",
        "SizeCode": "S",
        "UPC": "",
        "InvoicedQuantity": "1"
      }
    ]
  }

但我得到了输出

 "InvoiceItems": [
  {
    "InvoiceItemSizes": {
      "InvoiceLineNumber": "1",
      "InvoicedQuantity": "3",
      "SizeCode": "L",
      "UPC": "9348282095644"
    },
    "InvoiceLineNumber": "1",
    "InvoiceNumber": "101000005",
    "InvoicedQuantity": "3",
    "ProductInvoicedPrice": "39.00",
    "ProductName": "MF TAKE TWO JACKET",
    "ProductNumber": "CJKBC7BLKL"
  },
  {
    "InvoiceItemSizes": {
      "InvoiceLineNumber": "2",
      "InvoicedQuantity": "3",
      "SizeCode": "M",
      "UPC": "9348282095637"
    },
    "InvoiceLineNumber": "2",
    "InvoiceNumber": "101000005",
    "InvoicedQuantity": "3",
    "ProductInvoicedPrice": "39.00",
    "ProductName": "MF TAKE TWO JACKET",
    "ProductNumber": "CJKBC7BLKM"
  }

这里的区别是在输出中我期待InvloiceItemSize值进入[]但是在输出中我得到它来自{}。请帮帮我。

如果有人有正确的XSLT从XML转换为JSON，请提供给我。

由于

Answer 1

让我为你做谷歌：
https://github.com/doekman/xml2json-xslt
http://www.bramstein.com/projects/xsltjson/
http://www.bjelic.net/2012/08/01/coding/convert-xml-to-json-using-xslt/
Stackoverflow上的How to convert json to xml using xslt
（只是搜索＆＃34; xslt xml 2 json＆＃34;的四个第一个链接，有一些非常好的解释）

使用XSLT定义将XML转换为JSON

1 个答案: