Python和Selenium：StaleElementReferenceException

Question

我知道元素可能会刷新，但我仍然在找到旧元素。但是，我不知道如何修改它！请帮忙！

import datetime
from selenium import webdriver
from selenium.webdriver.common.by import By
from selenium.webdriver.support.ui import Select, WebDriverWait
from selenium.webdriver.support import expected_conditions as EC
from lxml import etree

driver = webdriver.Firefox()
driver.get("http://www.boci-pru.com.hk/english/mpf/mpfdisclaimer.aspx?to=http://www.boci-pru.com.hk/english/mpf/prices.aspx")
driver.find_element_by_xpath('//input[@value="I agree and wish to proceed"]').click()
driver.get("http://www.boci-pru.com.hk/english/mpf/prices_hist.aspx")
date = datetime.date.today() - datetime.timedelta(days=30)
fromday = Select(driver.find_element_by_xpath('//select[@name="fromday"]'))
frommonth = Select(driver.find_element_by_xpath('//select[@name="frommonth"]'))
fromyear = Select(driver.find_element_by_xpath('//select[@name="fromyear"]'))
fromyear.select_by_value(str(date.year))
frommonth.select_by_value(str(date.month))
fromday.select_by_value(str(date.day))
selFund = driver.find_element_by_xpath('//select[@name="selFund_code"]')
all_funds = selFund.find_elements_by_tag_name("option")
all_funds = [f for f in all_funds if len(f.get_attribute("value")) >= 2 and len(f.get_attribute("value")) < 6]

for fund in all_funds:
    fund.click()        # <--- this is where the issue starts
    print(fund.get_attribute("value"))
    driver.find_element_by_xpath('//input[@name="go"]').click()

Answer 1

如果在单击“go”按钮后刷新元素，则必须再次find元素 - 可能有更好的方法，但是代码的最直接修改将是像这样：

i = 0;
while True:
    selFund = driver.find_element_by_xpath('//select[@name="selFund_code"]')
    all_funds = selFund.find_elements_by_tag_name("option")
    all_funds = [f for f in all_funds if len(f.get_attribute("value")) >= 2 and len(f.get_attribute("value")) < 6]
    try:
        all_funds[i].click()
        print(fund.get_attribute("value"))
        driver.find_element_by_xpath('//input[@name="go"]').click()
        i += 1
    except IndexError:  # if i > len(all_funds)
        break

假设选项的顺序在迭代之间没有变化..

Answer 2

使用＆＃34;尝试＆＃34;和＆＃34;除了＆＃34;阻止如下所示：

for fund in all_funds:
    try:
        fund.click() 
        print(fund.get_attribute("value"))
    except:
        driver.find_element_by_xpath('//input[@name="go"]').click()