如何解决Winforms Control.Invoke错误？

Question

如何解决“ Control.Invoke必须用于与在分离的线程上创建的控件进行交互”错误异常

Socket serverSocket = new Socket(AddressFamily.InterNetwork, SocketType.Stream, ProtocolType.Tcp); 
serverSocket.Bind(new IPEndPoint(IPAddress.Loopback, portNo)); 
serverSocket.Listen(5); 
Socket client = serverSocket.Accept(); 
MessageBox.Show("Client Connected"); 

//Sent to Client 
NetworkStream ns = new NetworkStream(client); 
StreamWriter writer = new StreamWriter(ns); 
writer.AutoFlush = true; 
writer.WriteLine(sb.ToString()); 

//Receive from Client NetworkStream 
Stream nets = new NetworkStream(client); 
StreamReader reader = new StreamReader(nets); 
string clientIPAddress = reader.ReadLine();

Answer 1

通过做它说的话？这听起来像是在进行某种回调，但是（由于线程亲和性），您只能与其关联线程上的控件进行对话。所以：

string newAnswer = LongComplexCode(); // on worker thread here
someControl.Invoke((MethodInvoker) delegate {
    /* your work here, e.g. */
    someControl.Text = newAnswer; // on UI thread here
});