所以在某些时候,ajax调用会发送一个JSON,我将其转换为对象并存储在会话中:
if ( $deps = json_decode( $raw_json, true ) )
{
$pkgs = array();
foreach ( $deps['vector'] as $key )
{
if ( strcasecmp( $key['package'], $key['component'] ) == 0 )
{
$package = new Package();
$package->name = $key['package'];
$package->version = $key['version'];
$package->cxx_include = $key['cxx_inc'];
$package->cxx_link = $key['cxx_link'];
$pkgs[] = $package;
}
else
{
foreach( $pkgs as $package )
{
if ( $package->name == $key['package'] )
{
$component = new Component();
$component->name = $key['component'];
$component->cxx_link = $key['cxx_link'];
$package->components[] = $component;
}
}
}
}
$_SESSION['pkgs'] = serialize( $pkgs );
实际的课程很简单:
class Component
{
public $name;
public $cxx_link;
}
class Package
{
public $name;
public $version;
public $cxx_inclue;
public $cxx_link;
public $components = array();
}
在稍后的时候,我反序列化并尝试解析它们:
$pkgs = isset( $_SESSION['pkgs'] ) ? unserialize($_SESSION['pkgs']) : array();
foreach ( $pkgs as $package )
{
fwrite( $cmake, "find_package(" . $package->name . " " . $package->version . " " );
if ( count( $package->components ) > 0 )
{
fwrite( $cmake, "COMPONENTS " );
foreach ( $package->components as $component )
fwrite( $cmake, $component->name. " " );
fwrite( $cmake, "REQUIRED )\r\n" );
}
if ( isset( $package->cxx_include ) )
// ERROR here: undefined variable
fwrite( $cmake, "include_directories(${".$package->cxx_include."})\r\n" );
if ( isset( $package->cxx_link ) )
// ERROR here: undefined variable
fwrite( $cmake, "target_link_libraries($rapp_name ${".$package->cxx_link."})\r\n" );
foreach ( $package->components as $component )
{
if ( isset($component->cxx_link) )
// ERROR here: undefined variable
fwrite( $cmake, "target_link_libraries($rapp_name ${".$component->cxx_link."})\r\n" );
}
}
真正令我困惑的是,未定义的变量不是$ component-> cxx_link或$ package-> cxx_link,但我所显示的是JSON的实际值。
例如,如果JSON是:
{
"vector": [
{
"package": "Boost",
"version": "1.54",
"component": "Boost",
"cxx_inc": "Boost_INCLUDE_DIRS",
"cxx_link": "Boost_LIBRARIES"
},
{
"package": "Boost",
"version": "1.54",
"component": "date_time",
"cxx_inc": "",
"cxx_link": "Boost_DATE_TIME_LIBRARY"
},
{
"package": "Boost",
"version": "1.54",
"component": "filesystem",
"cxx_inc": "",
"cxx_link": "Boost_FILESYSTEM_LIBRARY"
},
{
"package": "Opencv",
"version": "3.0",
"component": "OpenCV",
"cxx_inc": "OpenCV_INCLUDE_DIRS",
"cxx_link": "OpenCV_LIBS"
},
{
"package": "Eigen3",
"version": "3.0",
"component": "Eigen3",
"cxx_inc": "EIGEN3_INCLUDE_DIR",
"cxx_link": ""
}
]
}
我得到了错误:
PHP Notice: Undefined variable: .Boost_INCLUDE_DIRS.
PHP Notice: Undefined variable: .Boost_LIBRARIES.
PHP Notice: Undefined variable: .OpenCV_INCLUDE_DIRS.
我设置类成员的值是多少。 如果我正确地理解了这一点,那么在JSON迭代期间的赋值操作会做一些浅拷贝吗?
编辑根据Barmar的评论,我删除了serialize / unserialize,并将类定义移动到使用这些类的每个文件的顶部。我不再得到自动加载错误,但我仍然得到完全相同的未定义变量错误。
答案 0 :(得分:4)
<强>修正:强>
所以问题是你使用双引号而不是单引号作为字符串。 PHP有一个叫变量变量的东西,你使用它是无意的(参见http://php.net/manual/en/language.variables.variable.php)。
将包含"${something}"
之类的每个字符串切换为单引号(或按照Alex提到的那样转义美元符号),你就可以了,即:
fwrite( $cmake, "include_directories(${".$package->cxx_include."})\r\n" );
将是
fwrite( $cmake, 'include_directories(${'.$package->cxx_include.'})'."\r\n" );
(请注意,您无法在单引号字符串中使用\r
或\n
。)
旧回答:
你的Package
课程中有拼写错误。
您将其分配给$package->cxx_include
,但实际名称缺少&#34; d&#34;。
class Package
{
public $name;
public $version;
public $cxx_inclue; // typo
public $cxx_link;
public $components = array();
}