Question

我有一个多维数组，如下所示：

Array
(
    [0] => Array
        (
            [0] => Title 1
            [1] => Some text ... US5801351017 ...
        )

    [1] => Array
        (
            [0] => Title 2
            [1] => Some text ... US0378331005 ...
        )

    [2] => Array
        (
            [0] => Title 3
            [1] => Some text ... //Note here that it does not contain an ISIN Code
        )
...

我正在尝试过滤掉与我的Regex符合ISIN代码的数组。上面的数组是由以下代码生成的：

$title = $html->find("h3.r a");
$titlearray = array_map(function($value){
    return trim($value->plaintext);
}, $title);

$description = $html->find("span.st");
$descriptionarray = array_map(function($value){
    $string = strip_tags($value);
    return $string;
}, $description);

$result1 = array();
foreach($titlearray as $key => $value) {
    $tmp = array($value);
    if (isset($descriptionarray[$key])) {
        $tmp[] = $descriptionarray[$key];
    }
    $result1[] = $tmp;
}

print_r($result1);

我编写了一些非常接近的代码，但并不真正unset不包含ISIN代码的数组。我的代码就是：

$title = $html->find("h3.r a");
$titlearray = array_map(function($value){
    return trim($value->plaintext);
}, $title);

$description = $html->find("span.st");
$descriptionarray = array_map(function($value){
    $match = array();
    $string = strip_tags($value);
    $pattern = "/[BE|BM|FR|BG|VE|DK|HR|DE|JP|HU|HK|JO|US|BR|XS|FI|GR|IS|RU|LB|"
            . "PT|NO|TW|UA|TR|LK|LV|LU|TH|NL|PK|PH|RO|EG|PL|AA|CH|CN|CL|EE|CA|"
            . "IR|IT|ZA|CZ|CY|AR|AU|AT|IN|CS|CR|IE|ID|ES|PE|TN|PA|SG|IL|US|MX|"
            . "SK|KRSI|KW|MY|MO|SE|GB|GG|KY|JE|VG|NG|SA|MU]{2}[A-Z0-9]{10}/";
    preg_match($pattern, $string, $match);
    return $match;
}, $description);

$merged = array();
$i=0;
foreach($descriptionarray as $value){
  $merged[$i] = $value;
  $merged[$i][] = $titlearray[$i];
  $i++;
}

print_r($merged);

给了我这些数组：

Array
(
    [0] => Array
        (
            [0] => US5801351017
            [1] => Title 1
        )

    [1] => Array
        (
            [0] => US0378331005
            [1] => Title 2
        )

    [2] => Array
        (
            [0] => Title 3
        )
...

如何摆脱与我的正则表达式不匹配的数组？我正在寻找的是这个输出：

Array
(
    [0] => Array
        (
            [0] => Title 1
            [1] => US5801351017
        )

    [1] => Array
        (
            [0] => Title 2
            [1] => US0378331005
        )
...

修改

@CasimiretHippolyte

根据他的回答，我现在有了这个代码：

$titles = $html->find("h3.r a");

$descriptions = $html->find("span.st");

$ISIN_PATTERN = "/[BE|BM|FR|BG|VE|DK|HR|DE|JP|HU|HK|JO|US|BR|XS|FI|GR|IS|RU|LB|"
            . "PT|NO|TW|UA|TR|LK|LV|LU|TH|NL|PK|PH|RO|EG|PL|AA|CH|CN|CL|EE|CA|"
            . "IR|IT|ZA|CZ|CY|AR|AU|AT|IN|CS|CR|IE|ID|ES|PE|TN|PA|SG|IL|US|MX|"
            . "SK|KRSI|KW|MY|MO|SE|GB|GG|KY|JE|VG|NG|SA|MU]{2}[A-Z0-9]{10}/";

$results = [];

foreach ($descriptions as $k => $v) {
    if (preg_match($ISIN_PATTERN, strip_tags($v), $m)) {
        $results[] = ['Title' => trim($titles[$k]->plaintext), 'ISIN' => $m[1]];
    }
}

print_r($results);

这会缩小我的数组，仅选择与正则表达式匹配的元素，但不会在'ISIN' => $m[1]下显示匹配项。它输出：

Array
(
    [0] => Array
        (
            [Title] => Title 1
            [ISIN] => 
        )

    [1] => Array
        (
            [Title] => Title 2
            [ISIN] => 
        )
...

进一步编辑

此代码解决了这个问题：

$titles = $html->find("h3.r a");

$descriptions = $html->find("span.st");

$ISIN_PATTERN = "/[BE|BM|FR|BG|VE|DK|HR|DE|JP|HU|HK|JO|US|BR|XS|FI|GR|IS|RU|LB|"
            . "PT|NO|TW|UA|TR|LK|LV|LU|TH|NL|PK|PH|RO|EG|PL|AA|CH|CN|CL|EE|CA|"
            . "IR|IT|ZA|CZ|CY|AR|AU|AT|IN|CS|CR|IE|ID|ES|PE|TN|PA|SG|IL|US|MX|"
            . "SK|KRSI|KW|MY|MO|SE|GB|GG|KY|JE|VG|NG|SA|MU]{2}[A-Z0-9]{10}/";

$results1 = [];

foreach ($descriptions as $k => $v) {
    if (preg_match($ISIN_PATTERN, strip_tags($v), $m)) {
        $results1[] = ['Title' => trim($titles[$k]->plaintext), 'ISIN' => $m[1]];
    }
}

$titlesarray = array_column($results1, 'Title');

$results2 = array_map(function($value){
    $match = array();
    $string = strip_tags($value);
    $pattern = "/[BE|BM|FR|BG|VE|DK|HR|DE|JP|HU|HK|JO|US|BR|XS|FI|GR|IS|RU|LB|"
            . "PT|NO|TW|UA|TR|LK|LV|LU|TH|NL|PK|PH|RO|EG|PL|AA|CH|CN|CL|EE|CA|"
            . "IR|IT|ZA|CZ|CY|AR|AU|AT|IN|CS|CR|IE|ID|ES|PE|TN|PA|SG|IL|US|MX|"
            . "SK|KRSI|KW|MY|MO|SE|GB|GG|KY|JE|VG|NG|SA|MU]{2}[A-Z0-9]{10}/";
    preg_match($pattern, $string, $match);
    return $match;
}, $descriptions);

$descriptionarray = array_column($results2, 0);

$result3 = array();
foreach($titlesarray as $key => $value) {
    $tmp = array($value);
    if (isset($descriptionarray[$key])) {
        $tmp[] = $descriptionarray[$key];
    }
    $result3[] = $tmp;
}

print_r($result3);

因为我需要一个快速的解决方案，所以我很快就把事情搞得一团糟。这是非常低效的，因为我使用额外的arrar_map()，将数组简化为简单数组，然后将它们连接在一起。除此之外，我重复我的正则表达式。

最后编辑

@CasimiretHippolyte答案是最有效的解决方案，并为使用$m[1]模式或$m[0]模式提供答案。

Answer 1

您可以使用简单的foreach以其他方式设计代码，并仅在找到ISIN代码时逐个构建结果项：

$titles = $html->find("h3.r a");
$descriptions = $html->find("span.st");

define ('ISIN_PATTERN', '~
 \b  # there is probably a word boundary at the begin of the ISIN code
 (?=([A-Z]{2}[A-Z0-9]{10})\b) # check the format before testing the whole alternation
                              # at the same time, the ISIN is captured in group 1
 (?: # so, this alternation is only here to make the pattern fail or succeed
     C[AHLNRSYZ]|I[DELNRST]|P[AEHKLT]|S[AEIGK]|A[ARTU]|B[EGMR]|L[BKUV]|M[OUXY]|T[HNRW]
     |E[EGS]|G[BGR]|H[KRU]|J[EOP]|K[RWY]|N[GLO]|D[EK]|F[IR]|R[OU]|U[AS]|V[EG]|XS|ZA
 )~x');

$results = [];

foreach ($descriptions as $k => $v) {
    if (preg_match(ISIN_PATTERN, strip_tags($v), $m))
        $results[] = [ 'ISIN' => $m[1], 'Title' => trim($titles[$k]->plaintext) ]; 
}

print_r($results);

注意：此代码未经过测试，可能会得到改进。几个想法：

停止使用simplehtml并使用DOMDocument和DOMXPath
手动模式的设计假设所有国家都是等概率的。如果不是这种情况，请重写以检查最新的国家/地区

如果preg_match与模式不匹配，则取消设置数组？

修改

1 个答案: