Question

我是一个真正的新手用PHP，但我只是想通过做的请通过向我展示如何加载整个json文件并仅输出包含名称的变量来帮助我：

假设我的file.json包含：

{ “类型”：“FeatureC”，”特征”：[   { “类型”： “功能”，“ID”：” GF”，”属性 ”：{“ 名称”：”美国”}，”几何 ”：{“ 类型 ”：“ 多边形”， ”坐标“：[[ [61.210817,35.650072]，[62.230651,35.270664]，[62.984662,35.404041]，[63.193538,35.857166]，[63.982896,36.007957]，[64.546479,36.312073]，[64.746105,37.111818]，[65.588948,37.305217]，[65.745631 ，37.661164]，[66.217385,37.39379]，[66.518607,37.362784]，[67.075782,37.356144]，[67.83,37.144994]，[68.135562,37.023115]，[68.859446,37.344336]，[69.196273,37.151144]，[69.518785,37.608997 ]，[70.116578,37.588223]，[70.270574,37.735165]，[70.376304,38.138396]，[70.806821,38.486282]，[71.348131,38.258905]，[71.239404,37.953265]，[71.541918,37.905774]，[71.448693,37.065645] [71.844638,36.738171]，[72.193041,36.948288]，[72.63689,37.047558]，[73.260056,37.495257]，[73.948696,37.421566]，[74.980002,37.41999]，[75.158028,37.133031]，[74.575893,37.020841]，[74.067552 ，36.836176]，[72.920025,36.720007]，[71.846292,36.509942]，[71.262348,36.074388]，[71.498768,35.650563]，[71.613076,35.153203]，[71.115019,34.733126]，[71.156773 ，34.348911]，[70.881803,33.988856]，[69.930543,34.02012]，[70.323594,33.358533]，[69.687147,33.105499]，[69.262522,32.501944]，[69.317764,31.901412]，[68.926677,31.620189]，[68.556932,31.71331 ]，[67.792689,31.58293]，[67.683394,31.303154]，[66.938891,31.304911]，[66.381458,30.738899]，[66.346473,29.887943]，[65.046862,29.472181]，[64.350419,29.560031]，[64.148002,29.340819] [63.550261,29.468331]，[62.549857,29.318572]，[60.874248,29.829239]，[61.781222,30.73585]，[61.699314,31.379506]，[60.941945,31.548075]，[60.863655,32.18292]，[60.536078,32.981269]，[60.9637 ，33.528832]，[60.52843,33.676446]，[60.803193,34.404102]，[61.210817,35.650072]]]}}，   { “类型”： “功能”，“ID”：” SA”，”属性 ”：{“ 名称 ”：“ 津巴布韦 ”}，“ 几何 ”：{“ 类型 ”：“ 多边形”， ”坐标“：[[ [31.191409，-22.25151]，[30.659865，-22.151567]，[30.322883，-22.271612]，[29.839037，-22.102216]，[29.432188，-22.091313]，[28.794656，-21.639454]，[28.02137，-21.485975]，[ 27.727228，-20.851802]，[27.724747，-20.499059]，[27.296505，-20.39152]，[26.164791，-19.293086]，[25.850391，-18.714413]，[25.649163，-18.536026]，[25.264226，-17.73654]，[26.381935 ，-17.846042]，[26.706773，-17.961229]，[27.044427，-17.938026]，[27.598243，-17.290831]，[28.467906，-16.4684]，[28.825869，-16.389749]，[28.947463，-16.043051]，[29.516834， -15.644678]，[30.274256，-15.507787]，[30.338955，-15.880839]，[31.173064，-15.860944]，[31.636498，-16.07199]，[31.852041，-16.319417]，[32.328239，-16.392074]，[32.847639， - 16.713398]，[32.849861，-17.979057]，[32.654886，-18.67209]，[32.611994，-19.419383]，[32.772708，-19.715592]，[32.659743，-20.30429]，[32.508693，-20.395292]，[32.244988，-21.116489 ]，[31.191409，-22.25151]]]}}

]}

并在我的output.php中输出如下名称：

姓名：美国姓名：津巴布韦

来自json文件，请给我举例说明并将我的技能提升到php世界。

Answer 1

$data = json_decode($your_json);
$type = $data->type;
var_dump($type); //

您可以阅读有关在php中解码json以及访问值here

的更多信息

从json文件

1 个答案: