Netezza的分组周将于周三开始，并在周二结束

Question

我需要将我列出的分组周数列为73天前开始分组，从星期三开始到星期二结束分组的那一周......可以这样做吗？

Select  date_part('week',b.INV_DT), sum( a.ORD_QTY) as Ordered, sum( a.SHIPPED_QTY) as Shipped
from fct_dly_invoice_detail a, fct_dly_invoice_header b, dim_invoice_customer c
where a.INV_HDR_SK = b.INV_HDR_SK
and b.DIM_INV_CUST_SK = c.DIM_INV_CUST_SK
and a.SRC_SYS_CD = 'ABC'
and a.NDC_NBR is not null 
and b.inv_dt between CURRENT_DATE - 73 and CURRENT_DATE
and b.store_nbr in (2851, 2963, 3249, 3385, 3447, 3591, 3727, 4065, 4102, 4289, 4376, 4793, 5209, 5266, 5312, 5453, 5569, 5575, 5892, 6534, 6571, 7110, 9057, 9262, 9652, 9742, 10373, 12392, 12739, 13870

Answer 1

你可以假装从星期三开始假一周，在星期二结束减去两天。

Select  date_part('week',b.INV_DT -2), sum( a.ORD_QTY) as Ordered, sum( a.SHIPPED_QTY) as Shipped
from fct_dly_invoice_detail a, fct_dly_invoice_header b, dim_invoice_customer c
where a.INV_HDR_SK = b.INV_HDR_SK
and b.DIM_INV_CUST_SK = c.DIM_INV_CUST_SK
and a.SRC_SYS_CD = 'ABC'
and a.NDC_NBR is not null 
and b.inv_dt between CURRENT_DATE - 73 and CURRENT_DATE
and b.store_nbr in (2851, 2963, 3249, 3385, 3447, 3591, 3727, 4065, 4102, 4289, 4376, 4793, 5209, 5266, 5312, 5453, 5569, 5575, 5892, 6534, 6571, 7110, 9057, 9262, 9652, 9742, 10373, 12392, 12739, 13870