Question

我想在产品属性上结合我的postgres查询结果。目前它给了我这些结果：

name        id   value                  sku     item_count
Item # 1    3    Item                   IT-EM1  3
Item # 1    2    006058465456           IT-EM1  3
Item # 2    3    Item                   IT-EM2  1
Item # 2    2    055045004505           IT-EM2  1

我希望它返回以下内容：

name       id#1   value#1    id#2    value#2         sku       item_count
Item # 1   3      Item       2       006058465456    IT-EM1    3
Item # 2   3      Item       2       055045004505    IT-EM2    1

id是产品属性id（2是GTIN，3是Brand，）值是该特定产品属性的值。我的查询如下：

SELECT
    p.name,
    l.property_id AS id,
    l.value AS value,
    v.sku,
    s.count_on_hand AS item_count,
FROM
    spree_variants v INNER JOIN
    spree_products p ON v.product_id = p.id LEFT OUTER JOIN
    spree_stock_items s ON v.id = s.variant_id INNER JOIN
    spree_product_properties l ON l.product_id = p.id
WHERE
    s.count_on_hand > 0

有什么想法吗？

Answer 1

自己回答这个问题。也许不是最优雅的解决方案，但是：

SELECT
    p.name,
    l.property_id AS id,
    l.value AS value,
    li.property_id AS id_two,
    li.value AS value_two,
    v.sku,
    s.count_on_hand AS item_count,
FROM
    spree_variants v INNER JOIN
    spree_products p ON v.product_id = p.id LEFT OUTER JOIN
    spree_stock_items s ON v.id = s.variant_id INNER JOIN
    spree_product_properties l ON l.product_id = p.id INNER JOIN
    spree_product_properties li ON li.product_id = p.id
WHERE
    s.count_on_hand > 0 AND
    l.property_id = 2 AND
    li.property_id = 3

再次将产品属性列添加为另一个变量（l和li），然后在WHERE中定义l.property_id = 2和li.property_id = 3

结合两个结果

1 个答案: