Question

我对php / sql非常新鲜。享受到目前为止我学到的东西，我现在对此感到困惑..

这是我目前的代码：

$query = "SELECT * FROM beings"; 
$result = mysql_query($query);
echo "<table><tr><th>Name</th><th>Location</th><th>Question</th><th>Time Submitted</th></tr>";
while ($row = mysql_fetch_array($result)) {   
    echo "<tr><td>" . $row['name'] . "</td><td>" . $row['location'] . "</td><td>" . $row["question"] . "</td><td>" . $row["submitted"] ."</td></tr>";
}
echo "</table>";
mysql_close();

我想要做的是，在表的右侧或左侧有一列复选框，底部有一个按钮，所以我可以选中一个框，然后从数据库中删除数据。

如何为在while循环中找到的每个条目添加一个复选框（这将是一个新的<td>条目）？对此有任何帮助非常感谢！谢谢大家！

Answer 1

Q1：如何添加复选框？ 答：echo "<tr><td>" . $row['name'] . "</td><td>" . $row['location'] . "</td><td>" . $row["question"] . "</td><td>" . $row["submitted"] ."</td><td><input type='checkbox' value='".$row['name']."' name='".$row['name']."'> </td></tr>";

这样做，它会在表格右侧添加一个复选框，每个复选框都有不同的名称（我假设你的表的'name'列具有唯一值）。

Q2：选择并删除这些条目 答：为此您可以添加此脚本

<script> 

$("#delete_form").on('submit',function(e){
    e.preventDefault();
    $.ajax({
        url:"delete_names.php",
        type:"POST",
        data:$("#delete_form").serialize(),
        success: function(response){
            $('#response').html(response);
        }
    });
});

HTML页面就像

    <form method="POST" id="delete_form">
    <?php
    $query = "SELECT * FROM beings"; 
    $result = mysql_query($query);
    while($row = mysql_fetch_array($result)){   
        echo "<tr><td>" . $row['name'] . "</td><td>" . $row['location'] . "</td><td>" . $row["question"] . "</td><td>" . $row["submitted"] ."</td><td><input type='checkbox' value='".$row['name']."'  name='".$row['name']."'> </td></tr>";
    }
    echo "</table>";
    mysql_close();

    ?>
    <input type="submit" id="#btn" value="Sumbit" />
    </form>
    <div id="response" > </div>

并且delete_name.php将类似于

<?php 
    //make connection to the database
    $con=mysqli_connect("localhost","my_user","my_password","my_db");
    foreach($_POST as $key=>$value){
        $query= "DELETE from beings WHERE name = ".mysqli_real_escape_string($con,$key);
        $result = mysql_query($query);
    }
?>

PS：您需要停止使用mysql_函数，因为它们已被弃用。使用mysqli_ / PDO代替。我已经使用过它们，这样你就可以理解解决这个问题的过程了。

Answer 2

没有jQuery的解决方案

如果你不想使用jQuery，那么将“action”添加到表单中，作为具有表单和复选框的同一个php页面。

<form method="POST"  action="<?php echo $_SERVER['PHP_SELF']; ?>" >
<?php
$query = "SELECT * FROM beings"; 
$result = mysql_query($query);
while($row = mysql_fetch_array($result)){   
    echo "<tr><td>" . $row['name'] . "</td><td>" . $row['location'] . "</td><td>" . $row["question"] . "</td><td>" . $row["submitted"] ."</td><td><input type='checkbox' value='".$row['name']."'  name='".$row['name']."'> </td></tr>";
}
echo "</table>";
mysql_close();

?>
<input type="submit" id="#btn" value="Sumbit" />
</form>

当提交此表单时，表单数据将被发布到此php文件本身，因此您需要在此页面上方添加表单处理和行删除代码（在html表单上方）。

<?php 
//make connection to the database
$con=mysqli_connect("localhost","my_user","my_password","my_db");
if(isset($_POST)){
    //if say there were 2 checkboxes checked with entries as 'a'and 'b'before submiting the form then $_POST['a']='a' and $_POST['b']='b'
    foreach($_POST as $key=>$value){
    //inside this loop we will make a query which will delete the name one by one
    //in the first iteration the $query will become
    //   DELETE from beings WHERE name = 'a'
        $query= "DELETE from beings WHERE name = ".mysqli_real_escape_string($con,$key);
        $result = mysql_query($query);
        // 'mysqli_real_escape_string' function is used to prevent SQL injection.That is a separate and very important topic.This function just say sanitize the data coming from user(which may or may not be tampered)
    }
}
?>

尝试在for循环中打印$ key $ value和$ query的值，以便更好地理解。

添加复选框到html表，然后就可以从sql数据库中删除数据

2 个答案: