我有2张桌子: 活动和注册。
事件字段:EventID和EventName
注册字段:MemberID和名称
我想拉出EventName和该人的姓名。如何使用模型执行此操作?
我的代码:
的模型
function getAll()
{
$query = $this->db->get('tblRegistration');
if( $query->num_rows() > 0) {
foreach ($query->result() as $row) {
$data[] = $row;
}
}
$query->free_result();
return $data;
}
控制器
public function getallevents() {
$this->load->model('events_model');
$data['records'] = $this->events_model->getAll();
$this->load->view('view-events', $data);
}
查看
foreach ($records as $row):
echo "<tr>";
echo "<td> $row->Name</td>";
// echo "<td> $row->intLocationID</td>";
echo "</tr>";
endforeach;
修改
好的,我已经从表中添加了我想要的数据。
模型
function getAll()
{
// get all the records from the schools table
$this->db->select('*');
$this->db->from('tblRegistration as reg');
$this->db->join('tblMeetRace as met', 'reg.intMeetRaceID = met.intEventID');
$query = $this->db->get();
// if the number of rows returned is more than 0
if( $query->num_rows() > 0) {
// loop through each record (row) and place that
// record into an array called $data
foreach ($query->result() as $row) {
$data[] = $row;
}
}
$query->free_result();
// return the array to the controller
return $data;
}
查看
foreach ($records as $row):
echo "<tr>";
echo "<td> $row->intMeetRaceID/td>";
echo "<td> $row->intEventID</td>";
echo "</tr>";
endforeach;
但我收到错误:
遇到PHP错误 严重性:警告
消息:为foreach()提供的参数无效 文件名:views / view-events.php
行号:89
答案 0 :(得分:0)
首先,您需要在事件表中添加另一列以存储MemberId
,例如memberid
。
完成后,当成员注册某个事件时,您可以将他的ID
存储在事件表中并将其关联起来。
然后您可以使用Joins
来获取数据
$this->db->select('*');
$this->db->from('registration as reg');
$this->db->join('events as evt', 'reg.id = evt.memberid');
$query = $this->db->get();