我有以下简单 图表中的节点:
digraph "graph.svg" {
graph [bgcolor="#333333" fontcolor=white fontname=Helvetica fontsize=16 label="Title" rankdir=TB]
0 [label=<<TABLE BORDER="0" CELLBORDER="1" CELLSPACING="0" CELLPADDING="2" BGCOLOR="#006699">
<TR>
<TD COLSPAN="2">Node Titel</TD>
</TR>
<TR>
<TD COLSPAN="2">Sieve</TD>
</TR>
<TR>
<TD CELLPADDING="0">
<TABLE BORDER="0" CELLPADDING="0" CELLSPACING="0" BGCOLOR="#006699">
<TR>
<TD BORDER="1">in 1</TD>
</TR>
<TR>
<TD BORDER="1">in 2</TD>
</TR>
</TABLE>
</TD>
<TD CELLPADDING="0">
<TABLE BORDER="0" CELLPADDING="0" CELLSPACING="0" BGCOLOR="#006699">
<TR>
<TD BORDER="1">out 1</TD>
</TR>
<TR>
<TD BORDER="1">out 2</TD>
</TR>
<TR>
<TD BORDER="1">out 3</TD>
</TR>
</TABLE>
</TD>
</TR>
</TABLE>> shape=plaintext]
}
产生此输出:
如何使边框对齐,使嵌套表之间不出现任何双边框? 我设法摆弄了CELLSPADING = -1 但我不认为这是要走的路? 我不能使用COLSPAN选项,因为输入和输出端口的大小是可变的,这就是我用输入和输出单元的嵌套表解决这个问题的原因。
答案 0 :(得分:1)
digraph "graph.svg" {
graph [bgcolor="#333333" fontcolor=white fontname=Helvetica fontsize=16 label="Title" rankdir=TB]
0 [label=<<TABLE BORDER="0" CELLBORDER="1" CELLSPACING="0" CELLPADDING="2" BGCOLOR="#006699">
<TR>
<TD COLSPAN="2">Node Titel</TD>
</TR>
<TR>
<TD COLSPAN="2">Sieve</TD>
</TR>
<TR>
<TD CELLPADDING="0" BORDER="0">
<TABLE BORDER="0" CELLPADDING="0" CELLSPACING="0" BGCOLOR="#006699">
<TR>
<TD BORDER="1">in 1</TD>
</TR>
<TR>
<TD BORDER="1">in 2</TD>
</TR>
</TABLE>
</TD>
<TD CELLPADDING="0" BORDER="0">
<TABLE BORDER="0" CELLPADDING="0" CELLSPACING="0" BGCOLOR="#006699">
<TR>
<TD BORDER="1">out 1</TD>
</TR>
<TR>
<TD BORDER="1">out 2</TD>
</TR>
<TR>
<TD BORDER="1">out 3</TD>
</TR>
</TABLE>
</TD>
</TR>
</TABLE>> shape=plaintext]
}