我在Yii2中调用其余api的url时遇到问题。我想打个网址:
http://localhost/index-dev.php/myapi/collection/18
其中18是Id。
在我的web.php配置中,我有以下代码,以及其他程序员的其他设置:
'urlManager' => [
'enablePrettyUrl' => true,
'showScriptName' => true,
'rules' => [
['class' => 'yii\rest\UrlRule', 'controller' => ['coding/nodes', 'coding/scales','myapi/collection']],
'<controller:\w+>/<id:\d+>' => '<controller>/view',
],
],
当我拨打我的网址时,我得到了
未找到(#404)
我做错了什么?
答案 0 :(得分:5)
我有同样的问题,你可以禁用prural
'urlManager' => [
'enablePrettyUrl' => true,
'showScriptName' => true,
'rules' => [
['class' => 'yii\rest\UrlRule', 'controller' => ['coding/nodes', 'coding/scales','myapi/collection']],
'<controller:\w+>/<id:\d+>' => '<controller>/view',
'pluralize' => false,
],
],
答案 1 :(得分:4)
您需要在URL中使用复数的模型类名来访问单个模型:
http://localhost/index-dev.php/myapi/collections/18
查看documentation of yii\rest\UrlRule:
上面的代码将创建一整套支持以下RESTful API端点的URL规则:
- &#39; PUT,PATCH用户/&lt; id&gt;&#39; =&GT; &#39;用户/更新&#39;:更新用户
- &#39;删除用户/&lt; id&gt;&#39; =&GT; &#39;用户/删除&#39;:删除用户
- &#39; GET,HEAD用户/&lt; id&gt;&#39; =&GT; &#39; user / view&#39;:返回用户的详细信息/概述/选项
- &#39; POST用户&#39; =&GT; &#39; user / create&#39;:创建新用户
- &#39; GET,HEAD用户&#39; =&GT; &#39; user / index&#39;:返回用户的列表/概述/选项
- &#39;用户/&LT; ID&GT;&#39; =&GT; &#39; user / options&#39;:处理用户的所有未处理动词
- &#39;用户&#39; =&GT; &#39; user / options&#39;:处理所有未处理的用户集合动词
答案 2 :(得分:3)
我建议为API创建单独的模块 并将您的UrlManager配置为...... :)
'urlManager' => [
'enablePrettyUrl' => true,
'enableStrictParsing' => true,
'showScriptName' => false,
'rules' => [
[
'class' => 'yii\rest\UrlRule',
'pluralize'=>false,
'controller' => ['v1/country','v1/user'],
'tokens' => [
'{id}' => '<id:\\w+>'
],
'extraPatterns' => [
'POST register' => 'register', //from url
'GET exists'=>'exists',
'POST login'=>'login',
'POST follow'=>'follow',
'POST category'=>'category',
'PUT profile'=>'profile',
'PUT change_password'=>'change_password',
'PUT feed_interested'=>'feed_interested',
],
]
],
]
更多细节@ Create Rest Api