QJsonObject插入:删除后出错()

时间:2015-05-18 06:06:17

标签: c++ qt qjsonobject

当我使用QJsonObject.insert()并传递一个QJsonObject(之前调用remove())作为参数时,它不能很好地工作。我认为在这里发布代码更为明确:

QJsonObject mainObj = myProJsonDoc.object();
        QJsonObject modulesObj = mainObj.take(QLatin1String("modules")).toObject();
        modulesObj.remove(QString::number(tempItem->moduleID));
        qDebug()<<modulesObj;
        qDebug()<<mainObj;
        mainObj.insert(QLatin1String("modules"),modulesObj);
        qDebug()<<mainObj<<(QJsonValue)modulesObj;

像这样,输出将是错误的:

QJsonObject({"0":{"info":"balabala..","input":{"0":""},"name":"test1","output":{"0":""}}})
QJsonObject({})
QJsonObject({"modules":{"":null}}) QJsonValue(object, QJsonObject({"0":{"info":"balabala..","input":{"0":""},"name":"test1","output":{"0":""}}}) )

如果删除该行,请使用remove():

QJsonObject mainObj = myProJsonDoc.object();
        QJsonObject modulesObj = mainObj.take(QLatin1String("modules")).toObject();
        //modulesObj.remove(QString::number(tempItem->moduleID));
        qDebug()<<modulesObj;
        qDebug()<<mainObj;
        mainObj.insert(QLatin1String("modules"),modulesObj);
        qDebug()<<mainObj<<(QJsonValue)modulesObj;

这次进展顺利:

QJsonObject({"0":{"info":"balabala..","input":{"0":""},"name":"test1","output":{"0":""}},"1":{"info":"balabala..","input":{"0":""},"name":"","output":{"0":""}}})
QJsonObject({})
QJsonObject({"modules":{"0":{"info":"balabala..","input":{"0":""},"name":"test1","output":{"0":""}},"1":{"info":"balabala..","input":{"0":""},"name":"","output":{"0":""}}}}) QJsonValue(object, QJsonObject({"0":{"info":"balabala..","input":{"0":""},"name":"test1","output":{"0":""}},"1":{"info":"balabala..","input":{"0":""},"name":"","output":{"0":""}}}) )

你知道为什么吗?

0 个答案:

没有答案