设计背景:
我正在尝试为以下数据库结构创建代码优先的EF6映射:
数据库设计如下:我们没有将“CustomerID”作为所有相关实体的外键(就业,费用,收入等),我们有一个CustomerRelationship表,它将包含CustomerID,然后“RelatedID”列,其中包含相关实体的密钥。例如,假设我为CustomerID = 1添加了一份就业记录,然后会发生以下情况:
在CustomerRelationship中创建记录,设置CustomerID = 1 RelatedID = {new autogenerated EmploymentID,简而言之5} CustomerRelationshipTypeID = 55(查找表中的Id表明了这一点 此记录属于就业类型)
- 醇>
在就业表中创建记录(EmploymentID = 5)
以上结构适用于与客户相关的所有实体。
我有为就业工作的关系映射,这是我的课程:
public abstract class EntityBase : IEntity
{
#region IEntity Members
public int Id { get; set; }
public DateTime CreatedDate { get; set; }
public int CreatedUserId { get; set; }
public int CreatedSource { get; set; }
public DateTime ModifiedDate { get; set; }
public int ModifiedUserId { get; set; }
public int? DataMigrationId { get; set; }
public bool IsActive { get; set; }
#endregion
}
public class Employment : EntityBase
{
// ... all properties here.. removed most so easier to read
public int EmploymentTypeId { get; set; }
**public virtual ICollection<EmploymentRelationship> EmploymentRelationships { get; set; }**
}
public EmploymentMap()
{
this.HasKey(t => t.Id);
ToTable("tblEmployment");
Property(t => t.Id).HasColumnName("EmploymentID");
// Mapping for all properties follow
}
public abstract partial class CustomerRelationship : EntityBase
{
public int CustomerId { get; set; }
public decimal? PercentageShare { get; set; }
public int CustomerRelationshipTypeId { get; set; }
public int RelatedId { get; set; }
}
public class EmploymentRelationship : CustomerRelationship
{
public virtual Employment Employment { get; set; }
}
public EmploymentRelationshipMap()
{
this.HasKey(t => t.Id);
Map<EmploymentRelationship>(m =>
{
m.Requires("CustomerRelationshipTypeID").HasValue(55).IsRequired(); // Define lookup value for type of employment
m.ToTable("tblCustomerRelationship");
});
Property(t => t.Id).HasColumnName("CustomerRelationshipID");
Property(t => t.CustomerId).HasColumnName("CustomerID");
Property(t => t.RelatedId).HasColumnName("RelatedID");
HasRequired(t => t.Employment)
.WithMany(t => t.EmploymentRelationships)
.HasForeignKey(t => t.RelatedId);
}
public class Customer : EntityBase
{
// Customer Properties...
public Customer()
{
EmploymentRelationships = new List<EmploymentRelationship>();
}
public virtual ICollection<EmploymentRelationship> EmploymentRelationships { get; set; }
}
public CustomerMap()
{
this.HasKey(t => t.Id);
ToTable("tblCustomer");
Property(t => t.Id).HasColumnName("CustomerID");
}
public class CustomerContext
{
public CustomerContext()
: base(SymmetryCopy.context_connectionstring_main)
{
}
public virtual DbSet<Customer> Customers { get; set; }
public virtual DbSet<Employment> Employments { get; set; }
#region Customer Relationship entity mappings
public virtual DbSet<EmploymentRelationship> EmploymentRelationships { get; set; }
#endregion
protected override void OnModelCreating(DbModelBuilder modelBuilder)
{
modelBuilder.Configurations.Add(new CustomerMap());
modelBuilder.Configurations.Add(new EmploymentMap());
#region Customer Relationship entity mappings
modelBuilder.Configurations.Add(new EmploymentRelationshipMap());
#endregion
}
}
CustomerRepo查询上下文并返回结果:
public class CustomerRepository : BaseRepository<Customer, CustomerContext>, ICustomerRepository
{
public CustomerRepository() :
base(new CustomerContext())
{
}
public async Task<List<Employment>> GetEmployments(int customerId)
{
List<Employment> employments = new List<Employment>();
using (var context = new CustomerContext())
{
var employmentRelationships = context.EmploymentRelationships.Where(l => l.CustomerId == customerId).ToList();
employments = employmentRelationships.Select(x => x.Employment).ToList();
}
return employments;
}
}
上述方法 GetEmployments 然后返回与CustomerID匹配的所有记录,其中CustomerRelationshipTypeID = 55(Employments的键值)。见下面的回报。
现在回答我的实际问题:
当我尝试连接另一个实体类型,即:Expense时,遵循与Employment相同的方法,创建Expense.cs,ExpenseMap.cs,ExpenseRelationship.cs,ExpenseRelationshipMap.cs,在ExpenseRElationshipMap.cs中包含以下内容:
public class ExpenseRelationshipMap
{
public ExpenseRelationshipMap()
{
HasKey(t => t.Id);
Map<ExpenseRelationship>(m =>
{
m.Requires("CustomerRelationshipTypeID").HasValue(60).IsRequired();
m.ToTable("tblCustomerRelationship"); // Define lookup value for type of Expense
});
Property(t => t.Id).HasColumnName("CustomerRelationshipID");
Property(t => t.CustomerId).HasColumnName("CustomerID");
Property(t => t.RelatedId).HasColumnName("RelatedID");
Property(t => t.PercentageShare).HasColumnName("PercentageShare");
HasRequired(t => t.Expense)
.WithMany(t => t.ExpenseRelationships)
.HasForeignKey(t => t.RelatedId);
}
}
一旦我创建了Map条目,如上所示,在查询GetEmployments()方法时,我现在得到以下异常:
“实体类型'费用关系'和'就业关系' 不能共享表'tblCustomerRelationship',因为它们不在 相同的类型层次结构或没有有效的一对一外键 与它们之间匹配主键的关系。“,
我错过了什么?
更新
根据jjj的评论,我更新了我的映射并创建了一个CustomerRelationship.cs基类。
public class Employment : EntityBase
{
public string EmployerName { get; set; }
public string EmployerContactFirstName { get; set; }
public string EmployerContactSurname { get; set; }
public virtual ICollection<EmploymentRelationship> EmploymentRelationships { get; set; }
}
public class Expense : EntityBase
{
public string Description { get; set; }
public virtual ICollection<ExpenseRelationship> ExpenseRelationships { get; set; }
}
public abstract class CustomerRelationship : EntityBase
{
public int CustomerId { get; set; }
public int? CustomerRelationshipTypeId { get; set; }
public int RelatedId { get; set; }
}
public class EmploymentRelationship : CustomerRelationship
{
public virtual Employment Employment { get; set; }
}
public class ExpenseRelationship: CustomerRelationship
{
public virtual Expense Expense{ get; set; }
}
public class CustomerRelationshipMap : BaseMap<CustomerRelationship>
{
public CustomerRelationshipMap()
{
ToTable("CustomerRelationship");
Map<EmploymentRelationship>(m => m.Requires("CustomerRelationshipTypeID").HasValue(55));
Map<ExpenseRelationship>(m => m.Requires("CustomerRelationshipTypeID").HasValue(60));
Property(t => t.Id).HasColumnName("CustomerRelationshipID");
Property(t => t.CustomerId).HasColumnName("CustomerID");
Property(t => t.RelatedId).HasColumnName("RelatedID");
}
public class EmploymentRelationshipMap : BaseMap<EmploymentRelationship>
{
public EmploymentRelationshipMap()
{
HasRequired(t => t.Employment)
.WithMany(t => t.EmploymentRelationships)
.HasForeignKey(t => t.RelatedId);
}
}
public class ExpenseRelationshipMap : BaseMap<ExpenseRelationship>
{
public ExpenseRelationshipMap()
{
HasRequired(t => t.Expense)
.WithMany(t => t.ExpenseRelationships)
.HasForeignKey(t => t.RelatedId);
}
}
public class CustomerContext : BaseContext
{
public CustomerContext()
: base(context_connectionstring_main)
{
}
public virtual DbSet<Customer> Customers { get; set; }
public virtual DbSet<Employment> Employments { get; set; }
public virtual DbSet<CustomerRelationship> CustomerRelationships { get; set; }
public virtual DbSet<EmploymentRelationship> EmploymentRelationships { get; set; }
public virtual DbSet<ExpenseRelationship> ExpenseRelationships { get; set; }
protected override void OnModelCreating(DbModelBuilder modelBuilder)
{
modelBuilder.Configurations.Add(new CustomerMap());
modelBuilder.Configurations.Add(new EmploymentMap());
modelBuilder.Configurations.Add(new CustomerRelationshipMap());
modelBuilder.Configurations.Add(new EmploymentRelationshipMap());
modelBuilder.Configurations.Add(new ExpenseRelationshipMap());
}
}
当我查询客户上下文时:
var relationships = context.CustomerRelationships.Where(l => l.CustomerId == customerId).ToList();
我得到以下异常:
“外键组件'relatedId'不是声明的属性 输入'EmploymentRelationship'。验证它是否未明确 从模型中排除,并且它是一个有效的原始属性。“,
答案 0 :(得分:7)
您需要为所有共享属性(包括主键)配置基类。
public class CustomerRelationshipMap : EntityTypeConfiguration<CustomerRelationship>
{
public CustomerRelationshipMap()
{
ToTable("tblCustomerRelationship");
Map<EmploymentRelationship>(m => m.Requires("CustomerRelationshipTypeID").HasValue(55));
Map<ExpenseRelationship>(m => m.Requires("CustomerRelationshipTypeID").HasValue(60));
HasKey(t => t.Id);
Property(t => t.Id).HasColumnName("CustomerRelationshipID");
Property(t => t.CustomerId).HasColumnName("CustomerID");
Property(t => t.RelatedId).HasColumnName("RelatedID");
}
}
然后,您应该能够在其他配置类中使用派生类特定的配置(但是,这不是我之前尝试过的)。
修改强>
此外,对于使用相同基类属性的派生类,不能有不同的外键关联。我可以想到几个选项,但这取决于你的情况:
EmploymentRelationship
- Employment
和ExpenseRelationship
- Expense
之间的关联分隔外键。Employment
和Expense
一个共同的基类 - 虽然这可能会破坏你想要做的目的.... CustomerRelationship
与Employment
/ Expense
之间的1:0..1关系分开(并摆脱EmploymentRelationship
和ExpenseRelationship
)Employment
和Expense
继承自CustomerRelationship
(并摆脱EmploymentRelationship
和ExpenseRelationship
)<强>来源强>