Question

我创建了一个D3可折叠树，可以按预期工作

var data = [
    { "name" : "Level 2: A", "parent":"Top Level" },
    { "name" : "Top Level", "parent":"null" },
    { "name" : "Son of A", "parent":"Level 2: A" },
    { "name" : "Daughter of A", "parent":"Level 2: A" },
    { "name" : "Level 2: B", "parent":"Top Level" }
    ];

var dataMap = data.reduce(function(map, node) {
 map[node.name] = node;
 return map;
}, {});

var treeData = [];
data.forEach(function(node) {
 // add to parent
 var parent = dataMap[node.parent];
 if (parent) {
  // create child array if it doesn't exist
  (parent.children || (parent.children = []))
   // add node to child array
   .push(node);
 } else {
  // parent is null or missing
  treeData.push(node);
 }
});

// ************** Generate the tree diagram  *****************
var margin = {top: 20, right: 120, bottom: 20, left: 120},
 // width = 960 - margin.right - margin.left,
 // height = 500 - margin.top - margin.bottom;
 
    width = 300 - margin.right - margin.left,
    height = 300 - margin.top - margin.bottom;
    
var i = 0;
var duration = 1000;
var tree = d3.layout.tree()
 .size([height, width]);

var diagonal = d3.svg.diagonal()
 .projection(function(d) { return [d.y, d.x]; });

var svg = d3.select("#tree").append("svg")
 .attr("width", width + margin.right + margin.left)
 .attr("height", height + margin.top + margin.bottom)
  .append("g")
 .attr("transform", "translate(" + margin.left + "," + margin.top + ")");

root = treeData[0];
  
update(root);

d3.select(self.frameElement).style("height", "800px");

function update(source) {

  // Compute the new tree layout.
  var nodes = tree.nodes(root).reverse(),
      links = tree.links(nodes);

  // Normalize for fixed-depth.
  nodes.forEach(function(d) { d.y = d.depth * 180; });

  // Update the nodes…
  var node = svg.selectAll("g.node")
      .data(nodes, function(d) { return d.id || (d.id = ++i); });

  // Enter any new nodes at the parent's previous position.
  var nodeEnter = node.enter().append("g")
      .attr("class", "node")
      .attr("transform", function(d) { return "translate(" + source.y0 + "," + source.x0 + ")"; })
      .on("click", click);

  nodeEnter.append("circle")
      .attr("r", 1e-6)
      .style("fill", function(d) { return d._children ? "lightsteelblue" : "#fff"; });

  nodeEnter.append("text")
      .attr("x", function(d) { return d.children || d._children ? -10 : 10; })
      .attr("dy", ".35em")
      .attr("text-anchor", function(d) { return d.children || d._children ? "end" : "start"; })
      .text(function(d) { return d.name; })
      .style("fill-opacity", 1e-6);

  // Transition nodes to their new position.
  var nodeUpdate = node.transition()
      .duration(duration)
      .attr("transform", function(d) { return "translate(" + d.y + "," + d.x + ")"; });

  nodeUpdate.select("circle")
      .attr("r", 4.5)
      .style("fill", function(d) { return d._children ? "lightsteelblue" : "#fff"; });

  nodeUpdate.select("text")
      .style("fill-opacity", 1);

  // Transition exiting nodes to the parent's new position.
  var nodeExit = node.exit().transition()
      .duration(duration)
      .attr("transform", function(d) { return "translate(" + source.y + "," + source.x + ")"; })
      .remove();

  nodeExit.select("circle")
      .attr("r", 1e-6);

  nodeExit.select("text")
      .style("fill-opacity", 1e-6);

  // Update the links…
  var link = svg.selectAll("path.link")
      .data(links, function(d) { return d.target.id; });

  // Enter any new links at the parent's previous position.
  link.enter().insert("path", "g")
      .attr("class", "link")
      .attr("d", function(d) {
        var o = {x: source.x0, y: source.y0};
        return diagonal({source: o, target: o});
      });

  // Transition links to their new position.
  link.transition()
      .duration(duration)
      .attr("d", diagonal);

  // Transition exiting nodes to the parent's new position.
  link.exit().transition()
      .duration(duration)
      .attr("d", function(d) {
        var o = {x: source.x, y: source.y};
        return diagonal({source: o, target: o});
      })
      .remove();

  // Stash the old positions for transition.
  nodes.forEach(function(d) {
    d.x0 = d.x;
    d.y0 = d.y;
  });
}

// Toggle children on click.
function click(d) {
  if (d.children) {
    d._children = d.children;
    d.children = null;
  } else {
    d.children = d._children;
    d._children = null;
  }
  update(d);
}

.node circle {
   fill: #fff;
   stroke: steelblue;
   stroke-width: 3px;
 }

 .node text { font: 12px sans-serif; }

 .link {
   fill: none;
   stroke: #ccc;
   stroke-width: 2px;
 }

<script src="https://cdnjs.cloudflare.com/ajax/libs/d3/3.4.11/d3.min.js"></script>
<body>
    <div id="tree"></div>
</body>

请参考设置宽度和高度的行（此示例现在已注释掉）

 // width = 960 - margin.right - margin.left,
// height = 500 - margin.top - margin.bottom;

这个宽度和高度为小部件提供了足够的空间来显示，所以一切正常。

但是，在某些情况下，页面上的空间有限，或者树中有多个节点无法容纳在分配的空间中。

我试图通过减少宽度和高度来重现这种情况

width = 300 - margin.right - margin.left,
height = 300 - margin.top - margin.bottom;

当发生这种情况时，树的一部分被切断，用户无法查看树的隐藏部分。

当树的高度或宽度超出分配的高度或宽度时，有没有办法提供滚动条？

也欢迎任何其他建议，以便用户查看缺失的数据。

谢谢。

Answer 1

一切似乎都运转良好：

http://jsfiddle.net/zcgmxff0/2/

将宽度和高度放在树元素上

#tree {
    width: 400px;
    height: 200px;
    overflow: scroll;
}

为D3小部件提供滚动条

1 个答案: